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3 years ago

1) what is the answer to 5(3x-2y)+2(x+2y)-3(3x-2y)?

1 answer:

4 0

So first we want to distribute. (#1)

So, using the distributive property, we can:

5 * 3x - 2y * 5 + 2x + 2 * 2y - 3 * 3x - 3 * 2y

or

15x - 10y + 2x + 4y - 9x - 6y

Now just combine like terms

8x -12y

So for #1 it should be a.

#2: 2x - 3 + 3x - 5

Combine Like Terms:

2x + 3x - 3 - 5

5x - 8

So it should be b.

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18,000

just use a calculator bro

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2 years ago

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Derive this equation <br>In (3-4Cosx)

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Step-by-step explanation:

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2 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

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2 years ago

Which is the solution to the inequality 1/4+x<5/8

Masteriza [31]

Answer:

x<3/8

Add me on instagram at skyy.thatdancer

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

x+1/4<5/8

Step 2: Subtract 1/4 from both sides.

x + 1/4 - 1/4 < 5/8 - 1/4

x<3/8

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3 years ago