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Radda [10]
3 years ago
8

1) what is the answer to 5(3x-2y)+2(x+2y)-3(3x-2y)?

Mathematics
1 answer:
vichka [17]3 years ago
4 0
So first we want to distribute. (#1)

So, using the distributive property, we can:

5 * 3x - 2y * 5 + 2x + 2 * 2y - 3 * 3x - 3 * 2y

or

15x - 10y + 2x + 4y - 9x - 6y

Now just combine like terms

8x -12y

So for #1 it should be a.

#2: 2x - 3 + 3x - 5

Combine Like Terms: 

2x + 3x - 3 - 5

5x - 8

So it should be b.
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7ft, 7ft ,and 9ft area of base and volume AREA O F BAE
elena-s [515]

Answer:

Answer below

Step-by-step explanation:

The volume is 7 x 7 x 9 (441)

Area = 441

Base is 9ft

6 0
3 years ago
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Factor this expression completely.<br><br> u^3 - v^3
Musya8 [376]

Completely factored form of u^3-v^3 is:

(u-v)(u^2+uv+v^2)

Step-by-step explanation:

Algebraic formulas are used to factorize the expression.

Given

u^3 - v^3

The formula involving cube with negative sign is:

a^3-b^3 = (a-b)(a^2+ab+b^2)

Using this formula:

u^3-v^3 = (u)^3 - (v)^3\\= (u-v)(u^2+uv+v^2)

Hence,

Completely factored form of u^3-v^3 is:

(u-v)(u^2+uv+v^2)

Keywords: Factorization

Learn more about factors at:

  • brainly.com/question/13063819
  • brainly.com/question/13219835

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7 0
3 years ago
In 10 words or less, explain what it means for two segments to be parallel.
ArbitrLikvidat [17]

Answer:

Two or more lines are parallel when they lie in the same plane and never intersect.

Step-by-step explanation:

8 0
2 years ago
Subtract. Express your answer in lowest terms. 10 5/11 - 4 2/11
Zigmanuir [339]

Answer:

6   3 /11

Step-by-step explanation:

10 5/11 - 4 2/11

since they already have a common denominator

  10   5/ 11

- 4   2 /11

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6   3 /11

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Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

  • \theta = 240°
  • r = 16 ft

\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
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\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

  • \theta = 60°
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\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
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