Answer:
Step-by-step explanation:
a_1 = 15
a_2 = a_1 - 3
a_2 = 15 - 3
a_2 = 12
a_3 = a_2 - 3
a_3 = 12 - 3
a_3 = 9
a_4 = a_3 - 3
a_4 = 9 - 3
a_4 = 6
a_5 = 3
a_6 = 0 I'm leaving these last two to expand
a_n = a1 - (n - 1)*d
a_n = 15 - (n - 1)*3
a_n = 15 - 3n + 3
a_n = 18 - 3n
Example
a_6 = 18 - 3*6
a_6 = 0
Problem B
t(1) = 108
t(1 + 1) = 1/3 * 108
t(2) = 36
t(3) = 1/3 * t2
t(3) = 1/3 * 36
t(3) = 12
t(4) =1/3 (t(3))
t(4) = 1/3 * 12
t(4) = 4
t(5) = t4 / 3
t(5) = 4 / 3
t(5) = 1.3333333
So the explicit definition is
t(n) = 108 (1/3)^(n - 1) You could simplify this a little bit by realizing that 108 is made of three 3s.
t(n) = 4 * 3^3 * (1/3)^(n - 1)
t(n) = 4 * (1/3) ^ (n - 4)
Example
t(5) = 108 (1/3)^4
t(5) = 108(1/81)
t(5) = 1.3333333
And using the simplified formula, you get.
t(5) = 4 * (1/3)^1
t(5) = 1.333333 which is the same thing as the original result.
C=2pier.
C= (2)(3.14)(3.5). Radius is 1/2 of diameter
C= 21.98 feet
Answer:It would be f(n)= f(n-1) +4 this is because f(n-1) means the previous term and you would add your 4 every time you gain.
Step-by-step explanation:
A-b=21
5a-2b=18
We can use substitution here. Take the first equation and solve for A. (Picking this one because it's easy)
a = 21+b
Plugin to the second equation:5(21+b)-2b=18
Simplify: 105 + 5b - 2b = 18
Simplify: 105 + 3b = 18
Subtract both sides: 3b = 18-105
Simplify: 3b = -87
Divide: b = -29
Plug back into the first: a=21+b
a = 21 - 29
a = -8
Option D
The method that is not correct is brandon's method.
