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2 years ago

What's the answerrrrrrrrrrrrrr

Mathematics

2 answers:

Evgesh-ka [11]2 years ago

5 0

I tnjnk is b I'm not sure

OLEGan [10]2 years ago

3 0

It's a I am 100% sure instead of asking get this app called scan math or photo math in your phone it gives both Answers and solving

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There are 30boys in a sporting club 20of them play hockey and 15 play volley ball each boy plays atleast one of the true game.il

Fed [463]

5 boys play both hockey and volleyball (30-20-15=5)

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2 years ago

Find the median of this set of data 34 36 30 37 40 30 42 a 37 b 35 c 36 d 30

shusha [124]

Answer:

Step-by-step explanation:

The median is the value that separates the higher half from the bottom half of the data sample (middle value).

We have

34, 36, 30, 37, 40, 30, 42

Write from the smallest to the largest number

30, 30, 34, 36, 37, 40, 42

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3 years ago

In the expression 5x + 15 = 150, you can start solving the problem

Gnoma [55]

Answer:

i think 2x

Step-by-step explanation:

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2 years ago

Read 2 more answers

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

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2 years ago

Segment AB is congruent to segment AB.This statement shows the blankkkkk property

kompoz [17]

Reflexive Property, the property where the quantity equals itself.

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2 years ago