WILL GIVE BRAINLEAST

You need to order carpet for a room that has a length that is twice its width. If the area of the room is 288 square feet, find

Aleksandr-060686 [28]

Answer: d) 12 ft

Step-by-step explanation:

Let x be the width of the room , the the length of the room will be 2x.

We consider the shape of room is rectangle.

We know that the area of rectangle is given by :-

$A=l\times w$ , where l is length and w is width.

Given : Area of the room is 288 square feet

$\Rightarrow 288=2x\times x\\\\\Rightarrow\ 2x^2=288\\\\\Rightarrow\ x^2=144\\\\\Rightarrow\ x=-\sqrt{144}=\pm12$

Since, width cannot be negative, so the width of the room = 12 feet.

3 0

3 years ago

E temperature t of a metal sphere is inversely proportional to the distance from the centre of the sphere (the origin (0, 0, 0))

olasank [31]

(-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.

<h3>How to calculate temperature?</h3>

The quantity or amount of radiation contained in material or item, as measured by a temperature or sensed by touch and stated on a numerical scale.

The temperature T of a ball bearing is inverse to the length first from the origin, which we consider to be the center of the ball. The temperature at the exact location

(x, y, z) is a point on the sphere, the temperature at this point is given by

$T(x,y,z)= \dfrac{k}{(x^2 +y^2+z^2)^{1/2}}$

Where k is constant, then we have

T(1, 2, 2) = k/3 = 170

k = 510

So

$T(x,y,z)= \dfrac{510}{(x^2 +y^2+z^2)^{1/2}}$

Then we have

$\rm \triangledown T = \left ( -\dfrac{510x}{(x^2 +y^2+z^2)^{1/2}}, -\dfrac{510y}{(x^2 +y^2+z^2)^{1/2}}, \dfrac{510z}{(x^2 +y^2+z^2)^{1/2}} \right )\\\\\\\triangledown T (1, 2, 2) = -\dfrac{510}{27} (1, 2, 2) =-\dfrac{170}{9} (1, 2, 2)$

Then the direction will be from (1, 2, 2) to (4, 3, 5) will be (3, 1, 3)

So u = (3/√19, 1/√19, 3/√19)

Then we get

$\rm \triangledown T \cdot u = \dfrac{-170}{9}(1, 2, 2) \cdot \left (\dfrac{3}{\sqrt{19}}, \dfrac{1}{\sqrt{19}}, \dfrac{3}{\sqrt{19}} \right )\\\\\\\triangledown T \cdot u = - \dfrac{170}{9\sqrt{19}} (3 + 2 + 6)\\\\\\\triangledown T \cdot u = -\dfrac{1870}{9\sqrt{19}}$

The direction of the greatest inverse in the temperature is given by any vector parallel to and having the same direction $\triangledown$ T. (-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.

More about the temperature link is given below.

brainly.com/question/11464844

#SPJ4

6 0

2 years ago

7. A fundraising group charges $0.25 per cookie and has a daily expense of $18. Which of the

marissa [1.9K]

Answer:

Look below

Step-by-step explanation:

To answer the question, you have to find out how much 49 sold cookies amounts to, so multiply 49 by however much it is per cookie.

Then, subtract the daily expense, $18, by the number you got from the total amount earned from the cookies sold, and that number would show the daily profit earned by selling 49 cookies.

Hope this helps :)

4 0

3 years ago

Please help.....................................................................

yarga [219]

The mean is every number added, then divided by the amount of numbers. range is the number that occurred most often. What does that get you?

7 0

3 years ago

The Toylot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A) under a norma

kotegsom [21]

Answer:

Test statistic = 3.1587

Step-by-step explanation:

We are given that the Toy-lot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A).

Also, a sample of eleven motors was tested, and it was found that the mean current was x = 1.20 A, with a sample standard deviation of s = 0.42 A.

So, Null Hypothesis, $H_0$ : $\mu$ = 0.8 { claim of 0.8 A is not low}

Alternate Hypothesis, $H_1$ : $\mu$ > 0.8 { claim of 0.8 A is too low}

Now, the test statistics used here will be;

T.S. = $\frac{Xbar - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 1.20 A

s = sample standard deviation = 0.42 A

n = sample size = 11 motors

So, Test statistics = $\frac{1.20 - 0.8}{\frac{0.42}{\sqrt{11} } }$ ~ $t_1_0$

= 3.1587

At 1% level of significance, t table gives a critical value of 2.764 at 10 degree of freedom. Since our test statistics is higher than the critical value so we have sufficient evidence to reject null hypothesis .

Therefore, we conclude that Toy-lot claim of 0.8 A is too low.

8 0

4 years ago