Plz help me I will mark u Brainiest
2 answers:
Answer:
(a) (8,3) => Quadrant I
x-axis = 8
y-axis = 3
(b) (9, -2) => Quadrant IV
x-axis = 9
y-axis = -2
(c) (-3.5, -6) => Quadrant III
x-axis = -3.5
y-axis = -6
Extra Information about quadrant:
Quadrant I = (+x, +y)
Quadrant II = (-x, +y)
Quadrant III = (-x, -y)
Quadrant IV = (+x, -y)
Answer: 1- quadrant 1 or top right
2- quadrant 4 or bottom right
3-quadrant 3 or bottom left
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Student 1 and 3.
Move the negative into the brackets,
positive becomes negative while two negatives make a positive.
Option C and D is correct .....
Answer:
maybe 0
Step-by-step explanation:
Answer:
C, A
Step-by-step explanation:
If you would like me to explain, I could but this would be difficult. Trust me.
This equation has no solution where 'a' and 'b'
are both non-zero real numbers.
You said 2a + 2b = 2a
Subtract 2a from each side: 2b = 0
'b' must be zero.
And it doesn't matter what the value of 'a' is.
As long as b=0, 'a' can be any number.
