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ale4655 [162]
3 years ago
15

Solve the following system of equations. 2x-3y=8 -2x+6y=-20

Mathematics
1 answer:
wolverine [178]3 years ago
3 0
Solve the following system:
{2 x - 3 y = 8 | (equation 1)
{6 y - 2 x = -20 | (equation 2)

Add equation 1 to equation 2:
{2 x - 3 y = 8 | (equation 1)
{0 x+3 y = -12 | (equation 2)

Divide equation 2 by 3:
{2 x - 3 y = 8 | (equation 1)
{0 x+y = -4 | (equation 2)


Add 3 × (equation 2) to equation 1:
{2 x+0 y = -4 | (equation 1)
{0 x+y = -4 | (equation 2)

Divide equation 1 by 2:
{x+0 y = -2 | (equation 1)
{0 x+y = -4 | (equation 2)

Collect results:
Answer:  {x = -2
                {y = -4
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4x-y=20 and -2x-2y=10
lara31 [8.8K]

You can use Substitution to solve this problem:


4x-y=20

-y=-4x+20

y=4x-20


Now you have two equations, and you use the first one to substitute into the second one.


y=4x-20     and     -2x-2y=10


-2x-2(4x-20)=10

-2x-8x+40=10

-10x+40=10

-10x=-30

-x=-3

x=3


Now that we have figured out what x is, we can substitute x in to one of the equations to figure out y.


4x-y=20       x=3

4(3)-y=20

12-y=20

-y=8

y=-8



<em><u>So your answer would be x=3 and y=-8</u></em>

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