Question

What is the value of the expression shown below if x = 3, y = 6, and z = 4? x² + 3yz

Answer 1

Answer:

$81$

Step-by-step explanation:

The initial expression:

$x^2+3yz$

Identify your values:

$x=3\\y=6\\z=4$

Substitute:

$(3)^2+3(6)(4)$

Following PEMDAS, nearly everything is in parentheses, so move to exponents:

$9+3(6)(4)$

Multiply $6$ and $4$:

$9+3(24)$

Multiply $3$ and $24$:

$9+72$

Simplify:

$81$