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RUDIKE [14]
3 years ago
11

Ted needs an average of at least 70 on his three history test he has scored already 85 and 60 on two test what is the minimum gr

ade ted need on his third test?
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0
So average=(total of scores)/(number of tests)
needs at least average of 70
at least is represented as greater than or equal to or the sign (<u>></u>)
70<u>></u>(total)/(number oftests)

since we have 3 tests, we have to have 3 scores so
70<u>></u>(x+y+z)/3
he scored 85 and 60
70<u>></u>(x+85+60)/3 (doesn't matter which to subsitute)
70<u>></u>(x+145)/3
multiply obht sides by 3
210<u>></u>x+145
subtract 145 from both sides
65<u>></u>x
he needs to get at leas 65 on his third test





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5 0
3 years ago
Evaluate 3x^2- 9 when x=-2
murzikaleks [220]

Answer:

3

Step-by-step explanation:

We know x = -2, so we can substitute -2 in for x

3x^2- 9

3*-2^2-9

Solve the exponent first (PEMDAS)

3*4-9

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6 0
3 years ago
Read 2 more answers
A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther
mariarad [96]
<h2>Answer:</h2>

<em><u>Recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\

Therefore, on checking, we observe that,

a_{n}=a_{n-1}+(n-1)^{2}

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

<u>At, </u>

<u>n = 1</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0

which is true.

<u>At, </u>

<u>n = 2</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1

Which is also true.

<u>At, </u>

<u>n = 3</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5

Which is true.

<u>At, </u>

<u>n = 4</u>

a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14

This is also true at the given value of 'n'.

<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

a_{n}=a_{n-1}+(n-1)^{2}

3 0
3 years ago
15. What is the dependent and independent variable in this scenario?
Montano1993 [528]
The dependent variable is 5 and the independent is 15
7 0
2 years ago
ITO
Setler [38]

Using the speed - distance relationship, the time left before the appointed time is 27 minutes.

<u>Recall</u><u> </u><u>:</u>

  • Distance = speed × time

  • Let time = t

<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>

  • Distance = 10 × (t + 3) = 10t + 30 - - - (1)

<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>

  • Distance = 12 × (t - 2) = 12t - 24 - - - - (2)

<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>

10t + 30 = 12t - 24

<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>

10t - 12t = - 24 - 30

-2t = - 54

<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>

t = 54 / 2

t = 27

Hence, the time left before the appointed time is 27 minutes.

Learn more : brainly.com/question/25669152

8 0
2 years ago
Read 2 more answers
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