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adell [148]
3 years ago
10

What is 7vr - (-7rv)=

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0

Answer:

14vr

Step-by-step explanation:

7vr - (-7rv)=

Subtracting a negative is like adding

7vr + (7rv)=

Changing the order of rv to vr

7vr + (7vr)=

Combing like terms

14vr

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Solve for x<br><br> -.02x = 1.6
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Answer:

-8

Step-by-step explanation:

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A bag of marbles contains 1 blue, 5 green, and 4 red marbles. If you take out 2 marbles, what is the probability that they are b
ehidna [41]
If you take out two marbles, and they both end up green, then it would be five marbles out of 10 because there are 5 green marbles but . Then it would be a 5/10 chance of getting two green marbles.






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Use multiplication to find three equivalent ratios<br> 11 : 9
dlinn [17]

11 : 9

×2 ×2

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11 : 9

×3 ×3

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11 : 9

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3 years ago
The health of the bear population in a park is monitored by periodic measurements taken from anesthetized bears. A sample of the
Vikki [24]

Answer:

182.167-2.03\frac{114.05}{\sqrt{36}}=143.580  

182.167+2.03\frac{114.05}{\sqrt{36}}=220.754  

So on this case the 95% confidence interval would be given by (143.580;220.754)  

Step-by-step explanation:

Assuming the following dataset:

77, 349,417,349, 167 , 225, 265, 360,205

145,335,40,139, 177,108, 163, 202, 22

123,439, 125,135, 86,43, 217,49, 156

119,178, 151, 61, 350, 312, 91, 89,89

We can calculate the sample mean with the followinf formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}= 182.167

And the sample deviation with:

s = \sqrt{\frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}}=114.05

The sample size on this case is n =36.

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=182.167 represent the sample mean  

\mu population mean (variable of interest)  

s=114.05 represent the sample standard deviation  

n=36 represent the sample size    

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

The point estimate of the population mean is \hat \mu = \bar X =182.167

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=36-1=35  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,35)".And we see that t_{\alpha/2}=2.03  

Now we have everything in order to replace into formula (1):  

182.167-2.03\frac{114.05}{\sqrt{36}}=143.580  

182.167+2.03\frac{114.05}{\sqrt{36}}=220.754  

So on this case the 95% confidence interval would be given by (143.580;220.754)  

5 0
3 years ago
How do I do this? It requires knowledge of fractional negative exponents. I've done problems like this, but never with a number
Allushta [10]

Answer: 16√2

Step-by-step explanation:

7 0
3 years ago
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