You're trying to find constants
such that
. Equivalently, you're looking for the least-square solution to the following matrix equation.
To solve
, multiply both sides by the transpose of
, which introduces an invertible square matrix on the LHS.
Computing this, you'd find that
which means the first choice is correct.
Answer:
<u>The original three-digit number is 417</u>
Step-by-step explanation:
Let's find out the solution to this problem, this way:
x = the two digits that are not 7
Original number = 10x+7
The value of the shifted number = 700 + x
Difference between the shifted number and the original number = 324
Therefore, we have:
324 = (700 + x) - (10x + 7)
324 = 700 + x - 10x - 7
9x = 693 - 324 (Like terms)
9x = 369
x = 369/9
x = 41
<u>The original three-digit number is 417</u>
Answer:
its company a
Step-by-step explanation:
Is means equals. The number before the words Less than means that number is subtracted from that number. 3 times a number, we don’t know the number so we use a variable, 3x. So..........
3x-5=10
The Geometric mean of 4 and 10 is 6.32
<u>Explanation:</u>
Given:
Two numbers are 4 and 10
Geometric mean, GM = ?
We know,
GM = ![\sqrt[n]{a_1 X a_2}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba_1%20X%20a_2%7D)
Where,
n = 2
Substituting the value we get"
![GM = \sqrt[2]{4 X 10} \\\\GM = \sqrt[2]{40} \\\\GM = 6.32](https://tex.z-dn.net/?f=GM%20%3D%20%5Csqrt%5B2%5D%7B4%20X%2010%7D%20%5C%5C%5C%5CGM%20%3D%20%5Csqrt%5B2%5D%7B40%7D%20%5C%5C%5C%5CGM%20%3D%206.32)
Thus, the Geometric mean of 4 and 10 is 6.32
