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AlekseyPX
3 years ago
10

The functions f(x) and g(x) are shown below:

Mathematics
2 answers:
Flura [38]3 years ago
6 0

Answer:

(A) is your answer. The graph of g(x) will eventually exceed the graph of f(x)

Step-by-step explanation:

avanturin [10]3 years ago
5 0

Answer:

the answer is a because i just got it correct on a test

Step-by-step explanation:

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Which inequality represents the following sentence?
Murrr4er [49]
<span>x – 12 ≥ 18 Let's break down the sentence and create an inequality from it. We'll use X to represent the number. "Twelve fewer than a number is at least 18." The "Twelve fewer than a number" indicates subtraction, so let's do that. X - 12 "is at least 18." would be a greater than or equal relationship. So we have X - 12 ≥ 18 And we're done. The desired equation is: x – 12 ≥ 18</span>
6 0
2 years ago
Read 2 more answers
A movie theater owner made this box plot to represent attendance at the matinee movie last month.
tatuchka [14]

Answer:

D? maybe, I'm not sure. it jsut makes the most sense.

5 0
3 years ago
Barbra can walk 3,200 meters in 24 minutes. How far can she walk in three minutes.
lisabon 2012 [21]

Answer:

Step-by-step explanation:

To find how far she can walk in 3 minutes, we need to find how fast she can walk in 1 minutes. We do this by dividing the distance she walked by the time she walked. Lets do so.

3200/24=133.33

She walks 133.33 meters per minute. Now to find her distance in 3 minutes w multiply this number by 3.

133.33*3=400

Barbra walks 400 meters every 3 minutes.

3 0
3 years ago
Arectangularplotoflandistobefencedinusingtwokinds of fencing. Two opposite sides will use heavy-duty fencing selling for $3 a fo
svlad2 [7]

Answer:

Dimensions of the rectangular plot will be 500 ft by 750 ft.

Step-by-step explanation:

Let the length of the rectangular plot = x ft.

and the width of the plot = y ft.

Cost to fence the length at the cost $3.00 per feet = 3x

Cost to fence the width of the cost $2.00 per feet = 2y

Total cost to fence all sides of rectangular plot = 2(3x + 2y)

2(3x + 2y) = 6,000

3x + 2y = 3,000 ----------(1)

3x + 2y = 3000

      2y = 3000 - 3x

      y = \frac{1}{2}[3000-3x]

      y = 1500 - \frac{3x}{2}

Now area of the rectangle A = xy square feet

A = x[1500-\frac{3x}{2}]

For maximum area \frac{dA}{dx}=0

A' = \frac{d}{dx}(1500x-\frac{3}{2}x^{2}) = 0

1500 - 3x = 0

3x = 1500

x = 500 ft

From equation (1),

y = 1500 - \frac{3}{2}\times 500

y = 1500 - 750

y = 750 ft

Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.

two fencing 3(500+500) = $3000

other two fencing 2(750+750) = $3000

8 0
3 years ago
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
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