Question

Graph the first six terms of a sequence where a, = 4 and r = 2.

Answer 1

The first six terms are {4,8,16,32,64,128}

Further explanation:

The given sequence will be a geometric sequence as common ratio is given.

So,

Common ratio = r = 2

First term = a = 4

The next terms will be obtained by multiplying each term with 2.

$a_1 = 4\\a_2 = 4*2 = 8\\a_3 = 8*2 = 16\\a_4 = 16*2 = 32\\a_5 = 32*2 = 64\\a_6 = 64*2 = 128\\So\ the\ first\ 6\ terms\ are \{4,8,16,32,64,128\}$

For graph, the placement number of terms will be taken along x-axis and the terms will be along y-axis.

The graph is attached herewith.

Keywords: Geometric sequence, Common ratio

Learn more about geometric sequence at:

• brainly.com/question/1522572
• brainly.com/question/2491745

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