Answer:
These are two equilateral triangles and all the sides of an equilateral triangle are equal. The question even says so so that's the answer, all the sides of the equilateral triangles are equal so all the sides equate to each other
secx=1/cosx
1. To solve this problem you must apply the following proccedure:
2. You have to verify if secx sinx=tanx, so, you have:
3. You know that secx=1/cosx, and tanx=sinx/cosx, therefore:
(secx)(sinx)
(1/cosx)(sinx)
sinx/cosx
tanx
- We know, sum of all angles of a triangle is 180°.
- Therefore, by the problem
72 + 64 + (4x+20) = 180
or, 156 + 4x = 180
or, 4x = 180 - 156
or, 4x = 24
or, x = 24 ÷ 4 = 6
<h3><em>Your </em><em>answer </em><em>is </em><em>6</em><em>.</em></h3>
Step-by-step explanation:
First,
(A intersect B) = {1,2,4,5} intersect {1,3,5,7}
= {1,5}
Now,
A'n B = (A) - (A intersect B)
= {1,2,4,5} - {1,5}
= {2,4}
Answer:
Domain: {0, 1, 2, 3, 4, 5, 6}
Range: {4, 4.5, 5, 5.5, 6, 6.5, 7}
