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diamong [38]
3 years ago
15

5^n-3= 1/25 What is the value of n

Mathematics
1 answer:
drek231 [11]3 years ago
6 0

Happy New Year from MrBillDoesMath!

Answer:

n =     log(76/25) / log(5)


Discussion:

5^n  -3 = 1/25  =>                                        (add 3 to both sides)

5^n =  3 + 1/25 = 73/25 + 1/25 = 76/25     (take log;s of both sides)

log(5^n) = log (76/25)  =>

n log(5) =  log(76/25) =>

n =            log(76/25) / log(5)

Thank you,

MrB

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160 is 120% of what number?
LuckyWell [14K]
120 % = 160

---------------------------------------------------------------------------
Find 1 % :
---------------------------------------------------------------------------
120% = 160
1% = 160 ÷ 120
1% = 4/3

---------------------------------------------------------------------------
Find 100% :
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1% = 4/3
100% = 4/3 x 100
100% = 133 1/3

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Answer: 160 is 120% of 133 1/3
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8 0
3 years ago
Read 2 more answers
A 16 ft monument consists of a rectangular prism and a square pyramid, as shown below. If the exposed surfaces of the monument a
icang [17]

Answer and Step-by-step explanation:

The actual answer is 348.

4 rectangles with area 60 each, which, when added together, equals 240.

1 square with area 36.

Each triangle face is 18 each, so 72.

<u>Add those together and the answer is 348 </u>ft^2<u> :).</u>

<u></u>

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4 0
3 years ago
The meat department of a local supermarket packages ground beef using meat trays of two sizes: 1 designed to hold 1 lb of meet a
r-ruslan [8.4K]

Answer:

c) 0.932

99% confidence interval for average weights of all packages sold in small meat trays.

(0.932 ,1.071)

Step-by-step explanation:

Explanation:-

Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation  of 0.18 lbs.

size of the sample 'n' = 35

mean of the sample x⁻= 1.01lbs

standard deviation of the sample 'S' = 0.18lbs

<u>The 99% confidence intervals are given by</u>

(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )

The degrees of freedom γ=n-1 =35-1=34

tₐ =  2.0322

99% confidence interval for average weights of all packages sold in small meat trays

(1.01 - 2.0322 \frac{0.18}{\sqrt{35} } , 1.01+2.0322 \frac{0.18}{\sqrt{35} } )

( 1.01 - 0.06183 , 1.01+0.06183)

(0.932 ,1.071)

<u>Final answer</u>:-

<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>

<u>(0.932 ,1.071)</u>

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Step-by-step explanation:

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