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The mean temperature for the first 4 days in January was 8°C. The mean temperature for the first 5 days in January was 7°C. What

ahrayia [7]

Answer : The 5th day = 3 Celsius

Explanation:
the average of the first 4 day is 8
Which mean the combine temp on the first 4 day is 8 x 4 = 32

Now on the first 5 day the average temp is 7

Then the combine temp on the first 5 day is 7 x 5 = 35

Find the 5th day

4 days combine temp + 5th day = the combine temp of 5 days

32 + 5th day = 35
5th day = 35-32
5th day temp = 3C

3 0

2 years ago

The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func

katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle ( $\frac{1}{3},\frac{1}4$ ).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A( $\frac{1}{3},\frac{1}4$ )

Let O be the origin i.e. (0,0)

Point B will be ( $\frac{1}{3},0$ )

Now, let us consider the right angled triangle $\triangle OBA$ :

Sides:

$Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}$

Using Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}$

$sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}$

$\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}$

$cos\angle AOB = \dfrac{Base}{Hypotenuse}$

$\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}$

$tan\angle AOB = \dfrac{Perpendicular}{Base}$

$\Rightarrow tan\angle AOB = \dfrac{3}{4}$

$cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}$

$\Rightarrow cosec\angle AOB = \dfrac{5}{3}$

$sec\angle AOB = \dfrac{Hypotenuse}{Base}$

$\Rightarrow sec\angle AOB = \dfrac{5}{4}$

$cot\angle AOB = \dfrac{Base}{Perpendicular}$

$\Rightarrow cot\angle AOB = \dfrac{4}{3}$

3 0

2 years ago

A package of 8 pens costs $1.09. Milo’s work to find the unit price of the pack is shown below.

Anuta_ua [19.1K]

I think the answer is C. "He made a place value error when dividing. If he would have divided 1.09 by 8, he would have found the price of each individual pen.

4 0

2 years ago

Read 2 more answers

Melissa had $20 to purchase candy for a party. She purchased 3.6 pounds of candy that cost $2.50 per pound. How much money does

sammy [17]

Answer:

1738

Step-by-step explanation:

7 0

2 years ago

LETTERS How many permutations are possible of the letters in the word<br> NUMBERS?

ziro4ka [17]