Question

Find an equation of the plane. the plane through the point (−4, 8, 10) and perpendicular to the line x = 5 + t, y = 2t, z = 1 − 2t

Answer 1

1) Find an equation of the plane. The plane that passes through the point (2, 3, 4) and contains the line x = 4t, y = 2 + t, z = 3 − t 2) Find an equation of the plane. The plane that passes through (6, 0, −3) and contains the line x = 2 − 4t, y = 1 + 5t, z = 2 + 2t 3) Find an equation of the plane. The plane that passes through the point (1, −1, 1) and contains the line with symmetric equations x = 2y = 5z 4) Find the point at which the line intersects the given plane. x = 2 − t, y = 1 + t, z = 3t; x − y + 5z = 14 5) Find the point at which the line intersects the given plane. x = 2 + 2t, y = 3t, z = 4 − 2t; x + 2y − z + 2 = 0 6) Find the point at which the line intersects the given plane. x = y − 2 = 2z; 2x − y + 2z = 2