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chubhunter [2.5K]
3 years ago
7

One angle of a parallelogram measures 150°. What are the measures of the other three angles in the parallelogram?

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
6 0

Answer:

30,150, and 30

Step-by-step explanation:

In a paralellogram, opposite sides add up to 180 degrees, hence, the answer is 30,150, and 30

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PLS HELP ME PLSS AND SHOW HOW YOU GOT YOUR ANSWER
ioda

Answer:

Step-by-step explanation:

3 0
2 years ago
Let f(x) = (5)^x+1 .Evaluate f (-3) without using a calculator
rewona [7]

Answer:

f\left(-3\right)=\frac{126}{125}

Step-by-step explanation:

Given

f\left(x\right)\:=\:\left(5\right)^x+1

Putting x = -3 to find f(-3)

f\left(-3\right)\:=\:\left(5\right)^{\left(-3\right)}+1

as

5^{-3}=\frac{1}{125}       ∵  \mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

so

f\left(-3\right)=\frac{1}{125}+1

\mathrm{Convert\:element\:to\:fraction}:\quad \:1=\frac{1\cdot \:125}{125}

f\left(-3\right)=\frac{1\cdot \:\:125}{125}+\frac{1}{125}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

f\left(-3\right)=\frac{1\cdot \:\:125+1}{125}

f\left(-3\right)=\frac{126}{125}      ∵ 1\cdot \:125+1=126

Thus,

f\left(-3\right)=\frac{126}{125}

6 0
3 years ago
Tori ran 4/5 Mile in 1/5 hour. write an equation for the distance in miles Y that she ran in X hours if she ran at a constant ra
nirvana33 [79]

Answer:

y=4x

Step-by-step explanation:

Let

y ----> the distance in miles

x ----> the time in hours

using proportion

\frac{y}{x}=\frac{(4/5)}{(1/5)}

Simplify

\frac{y}{x}=\frac{4}{1}

y=4x

This is a linear direct variation

The unit rate or speed is the slope of the linear equation

The unit rate is 4 miles/hour

6 0
3 years ago
Find the equation of the line passing<br> through the points (2, 4) and (3, 2).<br> y = [? ]x + [ ]
PtichkaEL [24]

Answer:

first find slope m

m=(4-2)/(2-3)

m= -2

so equation line is

y-y1=m(x-x1)

y-4=-2(x-2)

y-4=-2x+4

y=-2x+4+4

y=-2x+8

?=-2

7 0
3 years ago
Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
n^{2}  \neq 2
n \neq +or- \sqrt{2}
5 0
3 years ago
Read 2 more answers
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