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BARSIC [14]
3 years ago
9

Would I distribute or foil first -2(b-2)(b-2)

Mathematics
1 answer:
7nadin3 [17]3 years ago
7 0
You would distribute the -2 and the first b-2
-2xb= -2b
-2x-2= 2
So it would now be -2b - 2 (b-2)
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Find the average value fave of the function f on the given interval. f() = 5 sec2(/6), 0, 3 2
Inessa05 [86]

Answer:

f_{ave} = {\frac{10 }{3\pi }

Step-by-step explanation:

To find - Find the average value fave of the function f on the given interval. f(x) = 5 sec²(x/6), [0, 3\pi/2]

Proof -

We know that,

Average value of f in the interval [a, b] is -

f_{ave} = \frac{1}{b - a}\int\limits^b_a {f(x)} \, dx

Now,

Here a = 0, b = \frac{3\pi }{2}, f(x) = 5sec^{2}(\frac{x}{6} )

Now,

f_{ave} = \frac{1}{\frac{3\pi }{2}  - 0}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{2 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {5sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{10 }{3\pi }}\int\limits^{\frac{3\pi }{2} }_0 {sec^2 ({\frac{x}{6} }) } \, dx

      = {\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) }|^{\frac{3\pi }{2} }_0 \, ]

      = {\frac{10 }{3\pi }}[\ {tan({\frac{x}{6} }) - tan({0) } \, ]

      = {\frac{10 }{3\pi }}[ {1 - 0 }  ]

      = {\frac{10 }{3\pi }

⇒f_{ave} = {\frac{10 }{3\pi }

3 0
3 years ago
REVIEW:<br> -.<br> Find the zeros of the function: f(x)=-3x – 6
horrorfan [7]

Answer:x=-2

Step-by-step explanation:

You want to set up the equal to zero

Then add six to both sides

Then divide by -3x

6 0
3 years ago
Help please
MissTica

Answer:

243cm^3

Step-by-step explanation:

By Pythagoras' Theorem,

height of the prism ^2 + 5.4^2 = 7.8^2

height of the prism = ±√(7.8^2 -5.4^2) = ±5.6285cm (5s.f.) (rej. - 5.6285 since height > 0cm)

volume of the prism = 1/2 x 5.4 x 5.6285 x 16 = 243cm^3 (3s.f.)

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8 0
3 years ago
The population of a city decreases by 1.2% per year. If this year's population is
Anarel [89]

Answer:

Your answer

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Step-by-step explanation:

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3 years ago
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Answer:that hard

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