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Tema [17]
3 years ago
12

WHAT IS THE SURFACE AREA OF THE FIFURE?

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0
I think the correct answer is 560ft^2.
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Please can someone would help me with this:)
VMariaS [17]
The equation for the shadow length L.
Is L=0.72*h

Therefore at 123 feet the shadow length would be 88.56 feet
7 0
2 years ago
Read 2 more answers
PQR is a right-angled triangle. PQ = 16 cm. PR = 8 cm. Calculate the length of
vlada-n [284]
SOLUTION:

PQR is a right-angle triangle.

Therefore, to solve this problem, we will use Pythagoras theorem which is only applicable to right-angle triangles.

Pythagoras theorem is as displayed below:

a^2 + b^2 = c^2

Where c = hypotenuse of right-angle triangle

Where a and b = other two sides of right-angle triangle

Now we will simply substitute the values from the problem into Pythagoras theorem in order to obtain the length of QR.

c = PQ = 16cm

a = PR = 8cm

b = QR = ?

a^2 + b^2 = c^2

( 8 )^2 + b^2 = ( 16 )^2

64 + b^2 = 256

b^2 = 256 - 64

b^2 = 192

b = square root of ( 192 )

b = 13.8564...

b = 13.86 ( to 2 decimal places )

FINAL ANSWER:

Therefore, the length of QR is 13.86 centimetres to 2 decimal places.

Hope this helps! :)
Have a lovely day! <3
8 0
3 years ago
Which is the value of this expression when p=-2 and q=-1?
saul85 [17]

Answer:

D. 4

Step-by-step explanation:

[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4

8 0
3 years ago
Combine Like Terms :2y+7z-2z+4y+8+y+2
Viktor [21]

Answer:

7y + 5z + 10

Step-by-step explanation:

2y + 7z - 2z + 4y + 8 + y + 2

Like terms are terms that have the same variable part.

2y, 4y, y are like terms (remember that y is the same as 1y when you add)

7z, -2z are like terms

8, 2 are like terms

2y + 7z - 2z + 4y + 8 + y + 2 =

= 2y + 4y + y + 7z - 2z + 8 + 2

= 7y + 5z + 10

4 0
2 years ago
Y=x+1 and y=-x-3 in graphing,Substitution,and elemination
marysya [2.9K]

\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\GRAPHING\ \text{(look at the picture)}\\\\y=x+1\\for\ x=0\to y=0+1=0\to(0,\ 1)\\for\ x=-1\to y=-1+1=0\to(-1,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=0\to(-3,\ 0)\\\\Solution:\ (-2,\ -1)


SUBSTITUTION\\\\\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\\text{substitute}\ y=-x-3\ \text{to the first equation}\\\\-x-3=x+1\ \ \ \ |+3\\-x=x+4\ \ \ \ |-x\\-2x=4\ \ \ \ |:(-2)\\x=-2\\\\\text{substitute the value of x to the second equation}\\\\y=-(-2)-3=2-3=-1\\\\Solution:\ (-2,\ -1)


ELIMINATION\\\\\underline{+\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right}\ \ \ |\text{add both sides of the equations}\\.\ \ \ \ 2y=-2\ \ \ \ |:2\\.\ \ \ \ \ \ y=-1\\\\\text{put the value of y to the first equation}\\\\-1=x+1\ \ \ \ |-1\\x=-2\\\\Solution:\ (-2,\ -1)

5 0
3 years ago
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