3 years ago

WHAT IS THE SURFACE AREA OF THE FIFURE?

Mathematics

1 answer:

max2010maxim [7]3 years ago

7 0

I think the correct answer is 560ft^2.

You might be interested in

How many terms are in the binomial expansion of (3x 5)9? 8 9 10 11

swat32

Answer:

Step-by-step explanation:

5 0

1 year ago

This table shows the ratio of number of people to liters of ginger ale needed find the missing values

makvit [3.9K]

Answer:

2 and 6

Step-by-step explanation:

7 0

2 years ago

Add all of the times together into min.

tatuchka [14]

Answer:

422mins and 8sec

Step-by-step explanation:

အားလုံးကိုပေါင်းလိုက်

7 0

2 years ago

Find the mean median mode and range. 5, 8, 11, 13, 14, 15

AlexFokin [52]

Answer:

mean-11

mode-none

range-10

median-12

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The gas law for an ideal gas at absolute temperature T (in kelvins), pressure P (in atmospheres), and volume V (in liters) is PV

JulijaS [17]

Answer:

$\frac{dT}{dt}=3.78^{\circ}K/min$

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

$\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}$

What we have to do is the derivative of a product:

$\frac{d(PV)}{dt}=P\frac{dV}{dt}+V\frac{dP}{dt}$

Substituting, we have:

$\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}$

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

$\frac{dT}{dt}=\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}=\frac{(8atm)(0.16L/min)+(13L)(0.14atm/min)}{(10mol)(0.0821Latm/mol^{\circ}K)}$

And then just calculate:

$\frac{dT}{dt}=3.78^{\circ}K/min$

6 0

2 years ago