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3 years ago

Please help meeeeeee

Mathematics

1 answer:

My name is Ann [436]3 years ago

6 0

Answer:

y = 32.0°

Step-by-step explanation:

Using the sine ratio in the right triangle

siny° = $\frac{opposite}{hypotenuse}$ = $\frac{9}{17}$ , hence

y = $sin^{-1}$ ( $\frac{9}{17}$ ) ≈ 32.0°

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cestrela7 [59]

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for the school play adult tickets cost 4$ and children tickets cost 2$ natalie is working at the ticket counter and just sold 20

lilavasa [31]

Let us formulate the independent equation that represents the problem. We let x be the cost for adult tickets and y be the cost for children tickets. All of the sales should equal to $20. Since each adult costs $4 and each child costs $2, the equation should be

4x + 2y = 20

There are two unknown but only one independent equation. We cannot solve an exact solution for this. One way to solve this is to state all the possibilities. Let's start by assigning values of x. The least value of x possible is 0. This is when no adults but only children bought the tickets.

When x=0,
4(0) + 2y = 20
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When x=1,
4(1) + 2y = 20
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When x=2,
4(2) + 2y = 20
y = 6

When x=3,
4(3) + 2y= 20
y = 4

When x = 4,
4(4) + 2y = 20
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When x = 5,
4(5) + 2y = 20
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When x = 6,
4(6) + 2y = 20
y = -2

A negative value for y is impossible. Therefore, the list of possible combination ends at x =5. To summarize, the combinations of adults and children tickets sold is tabulated below:

Number of adult tickets Number of children tickets
0 10
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3 4
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4 years ago

Using like terms simplify-k+2(-2k-5)

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3 years ago

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trapecia [35]

Answer:

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Step-by-step explanation:

* Margo paid $550.00 for dance classes

* She paid a $50.00 registration fee

* She paid $25.00 for each week she was enrolled in the classes

* We need to find the number of weeks w she enrolled in the

dance classes

Lets write an equation of these information and solve it

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∵ The cost of of each week = $25

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Divide both sides by 25

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