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Trava [24]
3 years ago
15

What Is 3 2/6- 2/3?

Mathematics
2 answers:
stira [4]3 years ago
8 0
Okay, so don't worry about the whole number, 3, just yet. What you do is find a common denominator for the two fractions. You don't need to change 2/6, but you need to change 2/3 because you can multiply the bottom by 2 to equal 6 which gives you a common denominator. So you multiply 2/3 by two on both bottom and top, and you get 4/6. Now, you can subtract 2/6-4/6. You may have noticed a problem. You get a negative if you subtract the top. Here's how you fix that: Take that whole number, 3, and use it to make 2/6 an improper fraction. Here's how you do that: Take 3, multiply it by the denominator, 6, to get 18, then add the numerator, but keep the denominator. So you have 20/6 now, instead of 2/6, and you can subtract now and not get a negative number. Get that? Okay, so now you have 20/6-4/6. the denominator does not change, so you are only subtracting the top. 20-4=16, so now you have 16/6. You can reduce that by diving both bottom and top by 2, and get 8/3. Now you need to make it a mixed fraction. You do this by dividing the bottom into top. 8 divided by 3 is 2, with 2 left over. You put that 2 over the denominator, 3, so your final answer is 3 and 2/3. 
miss Akunina [59]3 years ago
6 0
Hello there.

What Is 3 2/6- 2/3?

Answer:2  \frac{2}{3}
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F(x)=3x-3<br><br>g(x) 3x^3+5<br>Find F(-3) and g(-2)
astra-53 [7]

Answer:

f(-3) = -12

g(-2) = -19

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = 3x - 3

g(x) = 3x³ + 5

f(-3) is <em>x</em> = -3 for function f(x)

g(-2) is <em>x</em> = -2 for function g(x)

<u>Step 2: Evaluate</u>

f(-3)

  1. Substitute in <em>x</em> [Function f(x)]:                                                                           f(-3) = 3(-3) - 3
  2. Multiply:                                                                                                             f(-3) = -9 - 3
  3. Subtract:                                                                                                            f(-3) = -12

g(-2)

  1. Substitute in <em>x</em> [Function g(x)]:                                                                         g(-2) = 3(-2)³ + 5
  2. Exponents:                                                                                                        g(-2) = 3(-8) + 5
  3. Multiply:                                                                                                            g(-2) = -24 + 5
  4. Add:                                                                                                                   g(-2) = -19
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Answer:

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