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Jobisdone [24]
4 years ago
14

Notebooks cost $1.20 each. This weekend they will be at a sale on for $.80, what percentage is the sale??

Mathematics
1 answer:
AlladinOne [14]4 years ago
7 0
0.8/1.2 = 0.6667
1 - 0.6667 = 0.3333

It is 33.33 % off
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Tell whether ΔABC and ΔDCB can be proven congruent.
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D. No, there isn’t enough information because only two pairs of corresponding sides can't be used to prove that two triangles are congruent.

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Can someone please explain this to me?
gladu [14]

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3 years ago
The general form of the equation of a circle is x2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is .
Readme [11.4K]

Answer:

(-21,-19)

\sqrt{849}

Standard form

Step-by-step explanation:

We are given the equation of circle

x^2+y^2+42x+38y-47=0

General equation of circle:

x^2+y^2+2gx+2fy+c=0

Centre: (-g,-f)

Radius: \sqrt{g^2+f^2-c}

Compare the equation to find f, g and c from the equation

g\rightarrow 21

f\rightarrow 19

c\rightarrow -47

Centre: (-21,-19)

Radius (r) =\sqrt{21^2+19^2+47}=\sqrt{849}

Standard form of circle:

(x+21)^2+(y+19)^2=849

The centre of circle at the point (-21,-19) and its radius is \sqrt{849}.

The general form of the equation of a circle that has the same radius as the above circle is standard form.

4 0
3 years ago
Read 2 more answers
The graphs below have the same shape. What is the equation of the red
anyanavicka [17]

Answer:

Option B is correct .

Step-by-step explanation:

According to Question , both the graph have same shape . If we look at the the first graph it cuts x - axis at (0 , 2) and ( 0 , -2) . Hence x = 2 and -2 are the zeroes of the equation .

And ,the given function is ,

\implies f(x) = 4 - x^2 \\\\\implies f(x) = 4-x^2=0 \\\\\implies 2^2-x^2=0\\\\\implies (2-x)(2+x) = 0 \\\\\boxed{\red{\bf \implies x = 2 , (-2) }}

<u>Hence ,we can can see that x = </u><u> </u><u>2</u><u> </u><u>and</u><u> </u><u>(</u><u>-</u><u>2</u><u>)</u><u> </u><u>are</u><u> </u><u>the</u><u> </u><u>zeroes </u><u>of </u><u>graph</u><u>. </u><u> </u>

This implies that if we know the zeroes , we can frame the Equation.

On looking at second parabola , it's clear that cuts x - axis at ( 1, 0 ) and (-1,0). So , 1 and -1 are the zeroes of the quadratic equation . Let the function be g(x) . Here , a and ß are the zeroes.

\implies g(x) = (x-\alpha)(x-\beta) \\\\\implies g(x) = (1+x)(1-x) \\\\\boxed{\pink{\bf \implies g(x) = 1 - x^2}}

<u>Hence </u><u>option </u><u>B</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u>

8 0
3 years ago
Read 2 more answers
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