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barxatty [35]
3 years ago
13

Amos, peter, and Carlos begin running around a circular track the same time, from the same start line. It takes Amos 12 minutes

to complete the lap around the track. It takes peter 9 minutes, and it takes Carlos 8 minutes to complete 1 lap around the track. If the three boys continue running around the track their same rate of speed, in how many mi utes will the three boys pass one another?
Mathematics
2 answers:
umka2103 [35]3 years ago
6 0
30?

Hope this help(Tell me if i'm wrong :])
alexgriva [62]3 years ago
4 0

Answer:

<h2>After 72 minutes they all meet again.</h2>

Step-by-step explanation:

Givens

  • Amos completes a lap in 12 minutes.
  • Peter completes a lap in 9 minutes.
  • Carlos completes it in 8 minutes.

Now, to find the time where the pass one another, we just need to find the Greatest Common Factor. Let's use the divisors and multiples of each number.

12: 1, 2, 3, 4, 6, 12, 24, 36, 48, 60, 72.

9: 1, 3, 9, 18, 27, 36, 45, 54, 63, 72.

8: 1, 2, 4, 8, 16, 24, 32, 40, 48, 56, 64, 72

Now, observe that Amos and Peter pass on another after 3 minutes, then again after 36 minutes.

Peter and Carlos pass one another after 72 minutes.

Actually, they all meet at the same time after 72 minutes.

Therefore, the answer is 72 minutes.

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Answer:

y = -1/4x + 2.5

or

y = -1/4x + 5/2

Step-by-step explanation:

First we know that a perpendicular line is one that intersects at a 90-degree angle. This is simply the negative inverse of the slope in our case. So, 4 turns into -1/4 and that is our new slope. Next we know that we want it to pass through the point (6,1). Right now our equation is y = -1/4x + b. We can plug (6,1) into this equation and solve.

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y = -1/4x + 2.5

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