Call the length a, the width b
Perimeter = (a+b) x 2
And since we have (a+b) x 2 = 43.6, a + b = 43.6 : 2 = 21.8
a + b = 21.8
a - b = 7
-> a + b + (a - b) = 28.8
2a = 28.8
a = 14.4
b = 7.4
So, the area of the rectangle is 14.4 x 7.4 = 106.56
The answer to, Is the Triangle with side lengths of 10 in., 24 in., and 26 in, a right triangle is: Yes. For right triangles, the sum of the squares of the shorter sides is equal to the square of the longer side. Thus, this is a right triangle if 10^2+24^2=26^2. Expanding these squares, we have 100+576=676, which is true. Thus, the triangle is right.
Answer:
7 : 8
Step-by-step explanation:
70 : 80 divided by 2 =
35 : 40 divided by 5 =
7 : 8
OR
70 : 80 divided by 10 =
7 : 8
Answer:
y = -9x + 14
Step-by-step explanation:
y + 4 = -9 (x -2)
y + 4 = -9x +18
y = -9x + 14
