Please help me with this problem

Mathematics

2 answers:

MAVERICK [17]3 years ago

5 0

Hey bro download Socratic or photomath!

inn [45]3 years ago

4 0

Answer: Option 1

<u>Step-by-step explanation:</u>

$\begin {array}{l|c|c||l}&\underline{\quad Length\quad}&\underline{\quad Width\quad}&\underline{\qquad Area\qquad}\\ Current&3x&x&3x\cdot x=3x^2\\Option\ 1\ (triple)&3(3x)=9x&3(x)=3x&9x\cdot 3x=27x^2\\Option\ 2\ (3\ closets)&3x&x&3(3x\cdot x)=9x^2\\\end{array}$

Option 1 has a greater area than option 2.

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stepan [7]

Did you not learn to factor?

6 0

3 years ago

3+5i/-2+3i perform operation

melisa1 [442]

Answer:

$\dfrac{9}{13}-\dfrac{19}{13}i$

Step-by-step explanation:

Remember $i^2=-1$

You are given the fraction $\dfrac{3+5i}{-2+3i}$

First, multiply the numerator and the denominator by -2-3i:

$\dfrac{3+5i}{-2+3i}=\dfrac{(3+5i)(-2-3i)}{(-2+3i)(-2-3i)}=\dfrac{(3+5i)(-2-3i)}{(-2)^2-(3i)^2}=\dfrac{(3+5i)(-2-3i)}{4-9i^2}=\dfrac{(3+5i)(-2-3i)}{4+9}$