D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)
Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1
Answer:
x = -2
Step-by-step explanation:
-6x - 29 = 5x - 7
Add -6x to both sides
-29 = 11x - 7
Add 7 on both sides
-22 = 11x
Divide
= 
x = -2
Step-by-step explanation:




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