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Tatiana [17]
3 years ago
6

What is the equation of the quadratic graph with a focus of (3, 4) and a directrix of y = 8? (1 point)

Mathematics
2 answers:
Marta_Voda [28]3 years ago
8 0
This question was already answered this is what the other person got.

ASHA 777 [7]3 years ago
4 0

Answer:

equation become (x -3)² =  -8(y - 6).

Step-by-step explanation:

Given  :  focus of (3, 4) and a directrix of y = 8.

To find : What is the equation of the quadratic graph.

Solution : We have given

Focus = (3, 4).

directrix  y = 8.

The standard form is (x - h)² = 4p (y - k),

where the focus is (h, k + p) and the directrix is y = k - p.

On comparing

(h, k + p) =  (3, 4).

h = 3 ,

From focus

k + p = 4 ------(1)

From directrix

y = k -p

k -p = 8 -------(2)

Adding both the equation 1 and 2

k + p = 4 ------(1)

k -p = 8 -------(2).

____________

2k = 12 .

On dividing by 2

k = 6.

Plug k =6 in equation 1

k + p = 4

6 + p = 4

P = -2 .

Plug all the values in standard equation :

(x - h)² = 4p (y - k),

(x - 3)² = 4(-2) (y - 6).

(x -3)² =  -8(y - 6).

Therefore, equation become (x -3)² =  -8(y - 6).

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A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and
Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.​

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

Hypotenuse^2=Base^2+Perpendicular^2

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

(9.85)^2=x^2+(x+5)^2

97.0225=x^2+x^2+10x+25

0=2x^2+10x+25-97.0225

0=2x^2+10x-72.0225

Here, a=2, b=10,c=-72.0225. Using the quadratic formula, we get

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}

x=\dfrac{-10\pm \sqrt{676.18}}{4}

Approximating the value, we get

x=\dfrac{-10\pm 26}{4}

x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}

x=\dfrac{16}{4},\dfrac{-36}{4}

x=4,-9

Distance cannot be negative so x\neq -9.

Now we have x=4

x+5=4+5

x+5=9

Therefore, the base is 4 m and the height is 9 m.

5 0
3 years ago
Which sets of side lengths could form a triangle? Choose all that apply.
Svetlanka [38]

Answer:

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natulia [17]

Answer:

<u><em>9 months</em></u>

Step-by-step explanation:

Principal= P= $1200

Rate=R= 15%

Interest= I= $135

Time= T= ?

I=P*R*T/100

135= 1200*15*T/100

135*100=18000*T

13500/18000=T

T= 0.75 years

T= 0.75*12= 9 months

3 0
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Answer:

0

Step-by-step explanation:

because

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I think the answer would be B.)
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