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Tatiana [17]
3 years ago
6

What is the equation of the quadratic graph with a focus of (3, 4) and a directrix of y = 8? (1 point)

Mathematics
2 answers:
Marta_Voda [28]3 years ago
8 0
This question was already answered this is what the other person got.

ASHA 777 [7]3 years ago
4 0

Answer:

equation become (x -3)² =  -8(y - 6).

Step-by-step explanation:

Given  :  focus of (3, 4) and a directrix of y = 8.

To find : What is the equation of the quadratic graph.

Solution : We have given

Focus = (3, 4).

directrix  y = 8.

The standard form is (x - h)² = 4p (y - k),

where the focus is (h, k + p) and the directrix is y = k - p.

On comparing

(h, k + p) =  (3, 4).

h = 3 ,

From focus

k + p = 4 ------(1)

From directrix

y = k -p

k -p = 8 -------(2)

Adding both the equation 1 and 2

k + p = 4 ------(1)

k -p = 8 -------(2).

____________

2k = 12 .

On dividing by 2

k = 6.

Plug k =6 in equation 1

k + p = 4

6 + p = 4

P = -2 .

Plug all the values in standard equation :

(x - h)² = 4p (y - k),

(x - 3)² = 4(-2) (y - 6).

(x -3)² =  -8(y - 6).

Therefore, equation become (x -3)² =  -8(y - 6).

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Answer:

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Step-by-step explanation:

Given value:

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k= 1 \to  s_1 = \frac{1}{1+1} - \frac{1}{1+2}\\\\

                  = \frac{1}{2} - \frac{1}{3}\\\\

k= 2 \to  s_2 = \frac{1}{2+1} - \frac{1}{2+2}\\\\

                  = \frac{1}{3} - \frac{1}{4}\\\\

k= 3 \to  s_3 = \frac{1}{3+1} - \frac{1}{3+2}\\\\

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S=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....\frac{1}{n+1}-\frac{1}{n+2}\\\\

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=\frac{1}{2}-\frac{1}{5}+\frac{1}{0+1}-\frac{1}{0+2}\\\\=\frac{1}{2}-\frac{1}{5}+\frac{1}{1}-\frac{1}{2}\\\\= 1 -\frac{1}{5}\\\\= \frac{5-1}{5}\\\\= \frac{4}{5}\\\\

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In point 2: \sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}

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k= 2 \to  s_1 = \frac{1}{(2+6)(2+7)}\\\\

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when s_n \ \ dt_{n \to 0}

S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(0+6)(0+7)}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{6 \times 7}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{42}\\\\=\frac{45+35+28+60}{2520}\\\\=\frac{168}{2520}\\\\=0.066

\boxed{\text{In point 2:} \sum ^{\infty}_{k = 1} \frac{1}{(n+6)(n+7)} = 0.066}

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