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Veseljchak [2.6K]
3 years ago
15

The perimeter of a triangle is 82 feet. One side of the triangle is 2 times the second side. The third side is 2 feet longer tha

n the second side. Find the length of each side.
Mathematics
1 answer:
andrezito [222]3 years ago
3 0

Answer:

first side=40

second side=20

third side=22

Step-by-step explanation:

LET THE SIDES OF THE TRIANGLES BE y

Perimeter=82

first side=2 x y = 2y

second side=y

third side=2 +y

2y + y + 2 + y=82

4y+2=82

4y= 82-2

4y=80

y=80/4

y=20

first side=2y=2(20)=40

second side=y=20

third side= 2 + y= 2 + 20 = 22

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sukhopar [10]

Answer:

\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}

Step-by-step explanation:

Given : \sqrt{2} (3\sqrt{2} +\sqrt{14})

Solution:

\sqrt{2} (3\sqrt{2} +\sqrt{14})

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Thus ,  \sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}

Thus the solution is irrational since square root 7 does not have a perfect square and equal to 6+2square root of 14

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A larger number is double the sum of 3 and a smaller number. The larger number is 2 less than 3 times the smaller number. If y r
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Y > x
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y = 3x-2
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