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Lostsunrise [7]
3 years ago
15

The price of an item was increased twice by the same percent. By what percent was the second increase if the item became 1.44 ti

mes more expensive?
Please help!!!!!!
Mathematics
1 answer:
horsena [70]3 years ago
8 0
First, let's write this as an equation.

f(x)= price of an item

p= percent increase

f(x)=xp^2

1.44x=xp^2

1.44=p^2

\sqrt{ 1.44}= \sqrt{p^2

p=1.2

1.2=120%

Answer: The second price was a 120% of the first price which means that the second increase was 20% more than the first price.

Hope this helps!

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Answer:

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Brainliest would be really appreciated. (need it to unlock chat)

Feel free to ask further questions if you feel like it.

Till then, have a nice day

Step-by-step explanation:

I 5m+2v=26

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I 5m+2v=26 devide by 2 on both sides

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Now put this whole thing in the other equation II, replacing the v there

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we found m, v is easy

now put m in an equation from the start, let's take equation I here

I 5m+2v=26

5*(3)+2v=26

15+2v=26 subtract 15 on both sides

2v = 11 devide by 2

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So we found m and v, prices for single items. we can proof this when we put m and v into a given equation and the if it equals a true value

m & v in II

II 3m+8v=53

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53=53

Seems legit.

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Step-by-step explanation:

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Step 1: Define equation

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Step 2: Find x-intercept

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