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3 years ago

Translate into an equation and solve; A number increased by 27 is 14. Find the number. ( SHOW STEP BY STEP )

Mathematics

1 answer:

NARA [144]3 years ago

8 0

X + 27 = 14
27-14 = 13
-13 + 24 = 14
the answer is -13

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13 is 29% of what number?

Zielflug [23.3K]

13/23% = 1300/23 (56.52)

<em>Therefore, 13 is 29% of 1300/23 (56.52)</em>

4 0

3 years ago

Can someone solve all the even problems in the picture?

liberstina [14]

Im pretty sure its 43

4 0

3 years ago

You are running a concession stand at a basketball game. You are selling hotdogs and sodas. Each hotdog cost $1.50 and each soda

Lubov Fominskaja [6]

Answer:

35 hotdogs

Step-by-step explanation:

You are running a concession stand at a basketball game. You are selling hotdogs and sodas.

Let the number of hot dogs be represented by x

The number of soda be represented by y

You sold a total of 87 hotdogs and sodas combined

x + y = 87

x = 87 - y

Each hotdog cost $1.50 and each soda cost $0.50. At the end of the night you made a total of $78.50.

Hence we have the equation:

$1.50 × x + $0.50 × y = $78.50

1.50x + 0.50y = 78.50

Substitute 87 - y for x

1.50(87 - y) + 0.50y = 78.50

130.5 - 1.50y + 0.50y = 78.50

Collect like terms

- 1.50y + 0.50y = 78.50 - 130.50

-1.00y = -52

y = -52/-1

y = 52 sodas

How many hotdogs did you sell?

Using the equation:

x = 87 - y

x = 87 - 52

x = 35 hotdogs

Hence, you sold 35 hotdogs

6 0

3 years ago

How do you do 2y,-4y by elimination?

AysviL [449]

2y-4y=-2y

That is the answer

6 0

3 years ago

Read 2 more answers

The 95% confidence interval for these parts is 56.98 to 57.05 under normal operations. A systematic sample is taken from the man

Nonamiya [84]

Answer:

Stop the line of production since the sample mean (56.96) is outside the confidence interval [ $CI_{0.95}$ = ( 56.98, 57.05 )]

Step-by-step explanation:

Given that;

95% confidence interval for these parts is 56.98 to 57.05

$CI_{0.95}$ = ( 56.98, 57.05 )

Sample mean = 56.96

We know that;

If the sample mean is within the confidence interval then, our decision is to keep the line operating as it is inside the confidence interval.

But if the sample mean is not within the confidence interval them, our decision is to stop the line of production as it is outside the confidence interval.

Now since our mean sample (56.96) does not lie between with the 95% confidence interval $CI_{0.95}$ = ( 56.98, 57.05 ).

Therefore, Stop the line of production since the sample mean (56.96) is outside the confidence interval [ $CI_{0.95}$ = ( 56.98, 57.05 )]

7 0

3 years ago