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Shalnov [3]
3 years ago
11

(Picture Included) 20 points - can someone solve 11, 12, 13, and 15?

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

11. 3(5) + 2(4)

15 + 8 = 13


12.  x= -12

13. -30

15. x = 44


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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Make the fractions have a common denominator.

\frac{3}{3} (\frac{y+4}{2y}) +\frac{x}{y} (\frac{y-2}{3}) =\frac{3y^2+10}{6y}\\\frac{3y+12}{6y} +\frac{2y^2-4y}{6y} =\frac{3y^2+10}{6y}\\\frac{2y^2-y+12}{6y} =\frac{3y^2+10}{6y}

Now that both sides of the equation have a common denominator, you can cancel out the denominators.

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Now, set the equation equal to zero and factor.

2y^2-y+12=3y^2+10\\-y^2-y+2=0\\(-y-2)(y-1)=0\\\\-y-2=0\\y=2\\\\y-1=0\\y=-1

The y-values are {-2, 1}

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