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sashaice [31]
3 years ago
14

Subtract the polynomials (7.8x - 3.4y + z) and (-9.2x + 4.8y - 2.1z)

Mathematics
2 answers:
qaws [65]3 years ago
6 0
17x -8.2y +3.1z , the subtraction flips the signs on the second set, and then you just add the same variables together.
Pavel [41]3 years ago
5 0
   7.8x - 3.4y + z
-(-9.2x + 4.8y - 2.1z)
-------------------------------
17x - 8.2 y 3.1z

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Molly has cups of sugar. She used cup of sugar. She wants to model a subtraction problem on a number line to find how much sugar
vovangra [49]
I am going off the assumption that by "She used a cup of sugar" you mean that she used 1 cup of sugar. Since the model shows that her first step starts with 1.5, that means that she loses 1 cup, and moves 1 unit to the left. She is left with 0.5 cups of sugar.
B. She only moves 1 unit to the left.
5 0
3 years ago
Read 2 more answers
Simplify each expression to a single trig function or number cosx(secx-cosx)
AlladinOne [14]
I did this test  b4, yours is answer #number 12

Convert things to their basic forms. 
<span>Remember a few identities </span>
<span>sin^2 + cos^2 = 1 so </span>
<span>sin^2 = 1 - cos^2 and </span>
<span>cos^2 = 1 - sin^2 </span>

<span>I'm going to skip typing the theta symbol, just to make things faster. Just assume it is there and fill it in as you work the problems. </span>

<span>Follow along to see how each problem was worked out. You'll catch on to the general technique. </span>

<span>====== </span>
<span>1. sec θ sin θ </span>
<span>1/cos * sin = sin/cos = tan </span>

<span>2. cos θ tan θ </span>
<span>cos * sin/cos = sin </span>

<span>3. tan^2 θ- sec^2 θ </span>
<span>sin^2 / cos^2 - 1/cos^2 </span>
<span>(sin^2 - 1)/cos^2 </span>
<span>-(1-sin^2)/cos^2 </span>
<span>-cos^2/cos^2 </span>
<span>-1 </span>

<span>4. 1- cos^2θ </span>
<span>sin^2 </span>

<span>5. (1-cosθ)(1+cosθ) </span>
<span>Remember (a+b)(a--b) = a^2 - b^2 </span>
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<span>6. (secx-1) (secx+1) </span>
<span>sec^2 -1 </span>
<span>1/cos^2 - 1 </span>
<span>1/cos^2 - cos^2/cos^2 </span>
<span>(1-cos^2)/cos^2 </span>
<span>sin^2/cos62 </span>
<span>tan^2 </span>

<span>7. (1/sin^2A)-(1/tan^2A) </span>
<span>1/sin^2 - 1/(sin^2/cos^2) </span>
<span>1/sin^2 - cos^2/sin^2 </span>
<span>(1-cos^2)/sin^2 </span>
<span>sin^2/sin^2 </span>
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<span>8. 1- (sin^2θ/tan^2θ) </span>
<span>1-sin^2/(sin^2/cos^2) </span>
<span>1 - sin^2*cos^2/sin^2 </span>
<span>1-cos^2 </span>
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<span>9. (1/cos^2θ)-(1/cot^2θ) </span>
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<span>1/cos^2 - sin^2/cos^2 </span>
<span>(1-sin^2)/cos^2 </span>
<span>cos^2/cos^2 </span>
<span>1 </span>

<span>10. cosθ (secθ-cosθ) </span>
<span>cos *(1/cos - cos) </span>
<span>1-cos^2 </span>
<span>sin^2 </span>

<span>11. cos^2A (sec^2A-1) </span>
<span>cos^2 * (1/cos^2 - 1) </span>
<span>1 - cos^2 </span>
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<span>12. (1-cosx)(1+secx)(cosx) </span>
<span>(1-cos)(1+1/cos)cos </span>
<span>(1-cos)(cos + 1) </span>
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<span>-(cos^2 - 1) </span>
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<span>13. (sinxcosx)/(1-cos^2x) </span>
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<span>14. (tan^2θ/secθ+1) +1 </span>
<span>(sin^2/cos^2)/(1/cos) + 2 </span>
<span>sin^2/cos + 2 </span>
<span>sin*tan + 2 </span>
5 0
3 years ago
To create voltage in a battery, you need a difference in potential between compounds. What is the difference between the zinc po
meriva

Answer:

V=1.17 v

Step-by-step explanation:

The difference in potential between two points can be described as: potencial of the iron less  potential of the zinc, that is: V= 0.76-(-0.41)

Which can be rewrite as: V= 0.76 v + 0.41 v

V=1.17 v

6 0
3 years ago
Read 2 more answers
. Y = -X²-2x+3<br> x=y=1
yarga [219]

Answer: y = 1/2 x + 3

hope this helped!! :)

4 0
4 years ago
In how many ways can a student answer 10 true or false questions on a test?
bezimeni [28]
2^10=1024 since there are two choices for each of the 10 questions
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