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sashaice [31]
3 years ago
14

Subtract the polynomials (7.8x - 3.4y + z) and (-9.2x + 4.8y - 2.1z)

Mathematics
2 answers:
qaws [65]3 years ago
6 0
17x -8.2y +3.1z , the subtraction flips the signs on the second set, and then you just add the same variables together.
Pavel [41]3 years ago
5 0
   7.8x - 3.4y + z
-(-9.2x + 4.8y - 2.1z)
-------------------------------
17x - 8.2 y 3.1z

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Plz help me fast Simplify t12/t6
Digiron [165]

Answer:

t^6

Step-by-step explanation:

when dividing exponents, you subtract (refer to exponent rule)

t^12 - t^6 = t^6

4 0
3 years ago
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One card is randomly selected from a deck of cards find the odds against drawing a seven
Stella [2.4K]

Answer:

\frac{3}{4}

Step-by-step explanation:

Probability of getting a 7 + Probability of not getting a 7 = 1.

Odds against drawing a 7 = Probability of not getting a 7.

We could calculate the probability of getting a 7 and subtract 1 from it to get the answer.

There a four sevens in a deck of card, one of each kind.

Probability of getting a 7 = $ P(7) = \frac{4}{52} = \frac{1}{13} $

$ \implies P(not \hspace{1mm} getting \hspace{1mm} a \hspace{1mm} 7) = 1 - P(7) $

$ \implies $ P(not getting a 7) $ = 1 - \frac{1}{13} = \frac{12}{13} $

4 0
4 years ago
(5+w)(w+4) in standard form
dlinn [17]

Answer:

  w² +9w +20

Step-by-step explanation:

Multiply it out, collect terms, and write as descending powers of w.

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7 0
3 years ago
3 questions in 1
MrRissso [65]

Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

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Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

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Step-by-step explanation:

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