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suter [353]
4 years ago
7

a rectangular room is 2 times as long as it is wide and the perimeter is 24 meters find the dimension of the room

Mathematics
1 answer:
GuDViN [60]4 years ago
3 0
24= 2l+2w
l=2w

Substitute for l
24= 2(2w)+2w
24= 6w
4=w

Plug in the w value
l=2(4)
l=8

Final answer: Length= 8 m, Width= 4 m
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All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

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4 years ago
Is 4y=16x a Direct variation
gizmo_the_mogwai [7]

In the given equation, as the value of <em>y</em> increase, the value of <em>x</em> also

increases.

  • Yes, 4·y = 16·x is a direct variation

Reasons:

A direct variation is a relationship that exists between two variables. It is

also known as a direct proportion which can be expressed as; y = k·x

Where <em>k</em> is a number

The given equation is 4·y = 16·x

Dividing both sides by 4 gives;

\displaystyle \frac{4 \cdot y}{4}  = \frac{16 \cdot x}{4} = \frac{4 \times 4 \cdot x}{4}

Which gives;

y = 4·x

Comparing the above equation with the equation for a direct variation gives;

y = 4·x

y = k·x

Therefore;

k = 4

The equation, y = 4·x, and therefore, the equation from which it is derived, 4·y = 16·x, is a direct variation.

Learn more about direct variation here:

brainly.com/question/6499629

6 0
3 years ago
Write an example of the associative property of addition
vfiekz [6]
The word "associative" comes from "associate" or "group";the Associative Property is the rule that refers to grouping. For addition, the rule is "<span>a + (b + c) = (a + b) + c</span><span>"; in numbers, this means 
</span>2 + (3 + 4) = (2 + 3) + 4. For multiplication, the rule is "<span>a(bc) = (ab)c</span>"; in numbers, this means2(3×4) = (2×3)4<span>. Any time they refer to the Associative Property, they want you to regroup things; any time a computation depends on things being regrouped, they want you to say that the computation uses the Associative Property.</span>
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3 years ago
Read 2 more answers
Find, leave your answers in terms of pie,
Yuri [45]
Area of square = 10x10
= 100
area of circle = pi(r)^2
= pi (5)^2
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area of shaded = 100 -25pi

circumference of circle = 2pi (r)
= 2pi(5)
= 10pi

perimeters of shaded = 10pi + 10 + 10
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8 0
2 years ago
A parabola can be drawn given a focus of (6,-1) and a directrix of y = 9. What can be said about the parabola?​
zavuch27 [327]

Answer:

Since the focus is at (-6,-11) and the directrix is at y=9:

 

The vertex is halfway between the focus and the directrix, so the vertex is at (-6,-1).  (Draw this on graph paper if that doesn't make sense.)

 

The general form (conics form) of a parabola:  4p(y-k)=(x-h)^2 (vertex is (h,k) and "p" is the distance between the focus and vertex (or between vertex and directrix)).

 

(h,k) = (-6,-1)

 

p = 10 (distance between focus and vertex), so 4p = 40.

 

Therefore:

 

40(y+1)=(x+6)^2

 

Or if you need to rearrange to "vertex form":  y=(1/40)(x+6)^2 - 1

Step-by-step explanation:

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3 years ago
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