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3 years ago

What is the additive inverse of the complex number 13-2

Mathematics

1 answer:

Svet_ta [14]3 years ago

5 0

Answer:

-13 + j*2

Step-by-step explanation:

The additive inverse of a complex number x = a +j*b

is a number y, such that

x + y = 0

This means that

y = -x = - a - j*b

Therefore

The additive inverse of 13 - j*2 is equal to

-(13 - j*2) = -13 +j*2

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