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erica [24]
3 years ago
6

How do I get EF in question 12

Mathematics
1 answer:
Zinaida [17]3 years ago
8 0
Check the picture below.

since the arcEF is 75°, then the central angle it is in is also 75°, and the radius is of course 2.4,

\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}~~
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad degrees\\
------\\
r=2.4\\
\theta =75
\end{cases}\implies s=\cfrac{(75)(\pi )(2.4)}{180}\implies s=\pi

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Which of the following expressions represents a function? (5 points) a {(1, 2), (4, −2), (8, 3), (9, −3)} b y2 = 16 − x2 c 2x2 +
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Answer: Option "a" is the only expression that represents a function.

Step-by-step explanation:

A function f(x) = y is a "operator" that takes an input element, x, and assigns it to only one output element, y.

So, if we have that for a given value of x.

f(x) = y and f(x) = h

where y and h are different values, then this is not a function, because is assigning the input value x to two different output values.

Let's see the different options:

a) {(1, 2), (4, −2), (8, 3), (9, −3)}

This points are of the form (x, y)

We can see that each value of x is assigned to only one value of y, so this can represent a function.

b)  y^2 = 16 − x^2

Ok, suppose that x = 0, then:

y^2 = 16 - 0 = 16

then we have that y*y = 16.

So y can take two different values:

y = 4 ---> 4*4 = 16

y = -4 ---> -4*-4 = 16.

So this is not a function.

c) 2x^2 + y^2 = 5

First, we want to isolate y in one side:

y^2 = 5 - 2*x^2

Here we have a similar case to the option b, and we can use a similar argument to prove that this is not a function, so we can discard this.

d) x = 7.

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4 years ago
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Step-by-step explanation:

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3 years ago
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3 years ago
There are two different clocks in Wendy's house, one is 20 minutes faster in a day, and the other is 30 minutes slower in a day.
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Answer:

The answer is below

Step-by-step explanation:

For the first clock that is 20 minutes faster in a day, that means it is \frac{20\ min}{60\ min/hr}=\frac{1}{3}hr faster every day. For it to show the correct time, the clock should be 24 hours faster.

Since 1 day = 1/3 hr faster

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Let x number of days be required to be 24 hr faster. To find x we use the formula:

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