Question

Plz help on both will give branlyist and thx

Answer 1

Answer:

Part 1) $132\ ft^{2}$

Part 2) $27\ ft^{2}$

Step-by-step explanation:

Part 1) we know that

The area of the figure is the area of one trapezoid multiplied by 2

Find the area of one trapezoid

$A=\frac{1}{2}(b1+b2)h$

we have

$b1=9\ ft$

$b2=15\ ft$

$h=11/2=5.5\ ft$

substitute

$A=\frac{1}{2}(9+15)5.5=66\ ft^{2}$

Find the area of the figure

$2*66\ ft^{2}=132\ ft^{2}$

Alternative Method

The area of the figure is equal to the area of a rectangle plus the area of triangle

so

$A=11*9+\frac{1}{2}(11)(15-9)\\ \\A=99+33\\\\A=132\ ft^{2}$

Part 2) we know that

The area of the hexagon is equal to the area of one triangle multiplied by 6

Find the area of one triangle

$A=\frac{1}{2}bh$

we have

$b=3\ ft$

$h=3\ ft$

substitute

$A=\frac{1}{2}(3*3)=4.5\ ft^{2}$

$6*4.5\ ft^{2}=27\ ft^{2}$