A cat jumps from a balcony. About how fast is the cat moving after 1.5 seconds?
2 answers:
Answer: The velocity of the cat is 14.7 m/s. Or the cat is moving with the speed of 14.7 m/s after jumping from the balcony.
Explanation:
The initial velocity of the cat ,u= 0 m/s
the final velocity of the cat, v=v
Acceleration due to gravity = g =
Time interval ,t = 1.5 s
Using First equation of motion:
The velocity of the cat is 14.7 m/s. Or the cat is moving with the speed of 14.7 m/s after jumping from the balcony.
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Answer:
Explanation:
There's a formula for this:
F being force, k being the spring constant, and displacement being the change in x
We are given the force and the spring constant, so this is essentially isolating the Δx term. Do 60N/120N per meter. The newtons cancel out and you get a final answer of Δx = 0.5 meters
Answer:
a
The height is
b
The horizontal distance is
Explanation:
From the question we are told that
The speed is
The angle is
The height of the cannon from the ground is h = 2 m
The distance of the net from the ground is k = 1 m
Generally the maximum height she reaches is mathematically represented as
=>
=>
Generally from kinematic equation
Here s is the displacement which is mathematically represented as
s = [-(h-k)]
=> s = -(2-1)
=> s = -1 m
There reason why s = -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half
a = -g = -9.8
So
=>
using quadratic formula to solve the equation we have
Generally distance covered along the horizontal is
=>
=>