How many pints are in 3 gallons?

The cash price of a bike is $3000. The bike can be bought on hire purchase by making a 25% down-payment and monthly payments of

horrorfan [7]

25% downpayment of $750 + $125 x 24 months

= $3750

8 0

2 years ago

Read 2 more answers

A rectangle has perimeter 28cm. Its area is 42sq.cm. Determine the dimensions of the rectangle. Include a diagram in your soluti

yawa3891 [41]

The dimensions of the rectangle are: b=9.65 cm and h=4.35 cm or b=4.35 cm and h= 9.65 cm.

<h3>Quadrilaterals</h3>

There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram. Each type is defined accordingly to its length of sides and angles. For example, in a rectangle, the opposite sides are equal and parallel and their interior angles are equal to 90°.

The area of a rectangle is equal to base x height (A=bh). The perimeter of a geometric figure is the sum of its sides. Thus, for a rectangle, the perimeter is 2b+2h.

<h3>System of Linear Equations</h3>

System of linear equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point at which the lines intersect.

The question gives:

Perimeter=28cm

Area= 42 cm²

If the perimeter is the sum of all sides of the rectangle, you have:

Perimeter= 2b+2h=28

If the area of the rectangle is 42cm², you have:

Area=bh=42 cm²

You can write a system of linear equations.

2b+2h=28 (1)

bh=42 (2)

From equation 2, you have $b=\frac{42}{h}$ . Then, you can replace it in equation 1.

$2*\frac{42}{h}+2h=28 \\ \\ 84+2h^2=28h\\ \\ 2h^2-28h+84=0 \; dividing\; by\; 2\\ \\ h^2-14h+42=0$

Now, you should solve the quadratic equation.

$h_{1,\:2}=\frac{-\left(-14\right)\pm \sqrt{\left(-14\right)^2-4\cdot \:1\cdot \:42}}{2\cdot \:1}$

$h_{1,\:2}=\frac{-\left(-14\right)\pm \:2\sqrt{7}}{2\cdot \:1}$

$h_1=\frac{-\left(-14\right)+2\sqrt{7}}{2\cdot \:1}=7+\sqrt{7}=9.65 cm$

$h_2=\frac{-\left(-14\right)-2\sqrt{7}}{2\cdot \:1}=7-\sqrt{7}=4.35cm$

If h1=9.65 cm, then $b_1=\frac{42}{9.65} =4.35 cm$ , and if h2=4.35 cm, then $b_1=\frac{42}{4.35} =9.65 cm$ .

Read more about the quadratic function here:

brainly.com/question/1497716

#SPJ1

8 0

1 year ago

Suppose that the populations of the United States and China both increase by 12 million people in one year. What would be the re

Jlenok [28]

Question:

Suppose that the populations of the United States and China both increase by 12 million people in one year. What would be the relative change for each country? Answer to the nearest tenth of a percent (1 decimal place). Make sure that you fill in each answer area before checking "How Did I Do?".

If you assume that the U.S. population is about 300 million, an increase of 12 million would result in a relative change of Number %.

If you assume that China has about 1 billion people, an increase of 12 million would result in a relative change of Number %.

Answer:

The relative change of the United States and China is 4% and 1.2%, respectively.

Step-by-step explanation:

Given

Represent population with p. So, we have:

United States

$\triangle p = 12\ million$

$p_1 =300\ million$

China

$\triangle p = 12\ million$

$p_1 =1\ billion$

Required

Determine the relative change for each country

Relative change, C is calculated as:

$C = \frac{\triangle p}{p} * 100\%$

For United States

$C = \frac{12\ million}{300\ million} * 100\%$

$C = \frac{12}{300} * 100\%$

$C = \frac{12 * 100}{300}\%$

$C = \frac{1200}{300}\%$

$C = 4\%$

For China

$C = \frac{12\ million}{1\ billion} * 100\%$

$C = \frac{12}{1000} * 100\%$

$C = \frac{12* 100}{1000} \%$

$C = \frac{1200}{1000} \%$

$C = 1.2\%$

The relative change of the United States and China is 4% and 1.2%, respectively.

3 0

2 years ago

What is the difference in volume between a sphere with radius r and a sphere with radius 0.3r?

REY [17]

The volume of the sphere of radius r is:
V1 = (4/3) * (pi) * (r ^ 3)
Where,
r: sphere radius:
The volume of the sphere of radius 0.3r is:
V2 = (4/3) * (pi) * ((0.3r) ^ 3)
Rewriting:
V2 = (4/3) * (pi) * (0.027 (r) ^ 3)
V2 = 0.027 (4/3) * (pi) * (r ^ 3)
V2 = 0.027V1
The difference is:
V1-V2 = V1-0.027V1 = V1 (1-0.027)
V1-V2 = 0.973 * (4/3) * (pi) * (r ^ 3)
Answer:
the difference in volume between a sphere with radius and a sphere with radius 0.3r is:
V1-V2 = 0.973 * (4/3) * (pi) * (r ^ 3)

8 0

2 years ago

Factor completely: 12a^2b–18ab^2–30ab^3

Goryan [66]

Answer:

6ab(2a-3b-5b²)

Step-by-step explanation:

6(2a²b-3ab²-5ab³)

6a(2ab-3b²-5b³)

6ab(2a-3b-5b²)

7 0

2 years ago