Answer:
11. Classification on basis of angles -<em> </em><em><u> </u></em><em><u>Acute</u></em><em><u> </u></em><em><u>angled</u></em><em><u> </u></em><em><u>triangle</u></em><em><u> </u></em>
Classification on basis of sides - <em><u>Isosceles</u></em><em><u> </u></em><em><u>triangle</u></em><em><u> </u></em>
12. Classification on basis of angles - <em><u>Right</u></em><em><u> </u></em><em><u>angled</u></em><em><u> </u></em><em><u>triangle</u></em><em><u>. </u></em>
Classification on basis of sides - <em><u>Scalene</u></em><em><u> </u></em><em><u>triangle</u></em><em><u> </u></em>
13. Classification on basis of angles - <em><u>Obtuse</u></em><em><u> </u></em><em><u>angled</u></em><em><u> </u></em><em><u>triangle</u></em><em><u>. </u></em>
Classification on basis of sides - <em><u>Isosceles</u></em><em><u> </u></em><em><u>triangle</u></em><em><u>. </u></em>
(g-h)(x) = 2x+1 -(<span>x-2)
</span>(g-h)(x) = 2x+1 - x + 2
(g-h)(x) = x + 3
Answer:
3.141592
Step-by-step explanation:
0.98438195063 im pretty sure
Note: It the given equation the coefficient of must be -16 instead of 16.
Given:
Consider the height of the water balloon over time can be modeled by the function
To find:
The maximum height of the water balloon after it was thrown.
Solution:
We have,
Here, leading coefficient is negative. So, it is a downward parabola and vertex of a downward parabola, is the point of maxima.
If a parabola is , then
Here, . So,
Now, put x=5 in the given equation.
The vertex of the given parabolic equation is (5,450).
Therefore, the maximum height of the balloon is 450 units after 5 units of time.