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3 years ago

Answer as a mixed. Nnmber (if possible) 8 4/5 ÷ 10/3

Mathematics

2 answers:

tangare [24]3 years ago

7 0

2 16/25 is what i think it is

kogti [31]3 years ago

7 0

First keep 4/5 the same
Then change the division to a multiplication sign since I'm guessing you know how to multiply fractions?
Then flip flop 10/3 so now it's 3/10
So your equation should now be 4/5 x 3/10
It's 12/50 then simplify and your final answer is : 6/25

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Write in exponential form:<br><br> 5 * 5 * (-x) * (-x) * (-x) * (-x)

exis [7]

Answer:c

Step-by-step explanation:

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4 years ago

Which equation represents the graphed function?

makvit [3.9K]

The equation y = –2 x + 3 represents the graphed function.

Answer: Option A

<u>Step-by-step explanation:</u>

As per the mapping points in the attached figure, A (0, 3) and B (1, 1)

Step 1: Find the slope of the line.

We know that the formula to calculate the slope between two points is equal to

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\left(x_{1}, y_{1}\right)=(0,3) \text { and }\left(x_{2}, y_{2}\right)=(1,1)$ . So, the slope ‘m’ would be

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Step 2: Find the y-intercept

We know that the y-intercept is the value of y when the value of x is equal to zero. In this problem the y-intercept is the point A (0, 3)

Step 3: Find the equation of the line into slope-intercept form

We know that the equation of the line into slope-intercept form is equal to

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We have m = - 2 and b = 3 as b is equal to the y-coordinate of the y-intercept. Substitute these, we get

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8 0

3 years ago

Read 2 more answers

Use a surface integral to find the general formula for the surface area of a cone with height latex: h and base radius latex: a(

BlackZzzverrR [31]

We can parameterize this part of a cone by

$\mathbf s(u,v)=\left\langle u\cos v,u\sin v,\dfrac hau\right\rangle$

with $0\le u\le a$ and $0\le v\le2\pi$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=\sqrt{1+\dfrac{h^2}{a^2}}u\,\mathrm du\,\mathrm dv$

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$\displaystyle\iint_{\mathcal S}\mathrm dS=\sqrt{1+\frac{h^2}{a^2}}\int_{v=0}^{v=2\pi}\int_{u=0}^{u=a}u\,\mathrm du\,\mathrm dv=a^2\sqrt{1+\frac{h^2}{a^2}}\pi=a\sqrt{a^2+h^2}\pi$

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3 years ago

Suppose that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally distributed with a mean of 3.1

arlik [135]

Answer:

std deviation = 1.641

Step-by-step explanation:

Given that the TSH (Thyroid Stimulating Hormone) levels among healthy individuals are normally distributed with a mean of 3.1 units/mL.

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4 years ago

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LekaFEV [45]

Answer:

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4 years ago