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iVinArrow [24]
3 years ago
10

a bakery has a fixed cost of $119.75 per day plus $2.25 for each pastry. the bakery would like to keep its daily costs at or bel

ow $500 per day. what is the maximum number of pastries that can be baked each day?
Mathematics
1 answer:
murzikaleks [220]3 years ago
3 0
We can set up an inequality.

119.75+2.25x\le~500

Subtract 119.75 to both sides:

2.25x\le~380.25

Divide 2.25 to both sides:

x\le~169

So the maximum number of pastries that can be baked each day is 169.
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katrin2010 [14]

Answer:

x=0.75

Step-by-step explanation:

Hope this helps!

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3 years ago
Find the total travel time: Depart 5:30 pm MST Arrive 9:20 pm CST.
Ivan

Answer:

2 hour 50 minutes

Step-by-step explanation:

Given data: Departure = 5:30 pm MST, Arrive = 9:20 pm CST

Note that MST is the time zone 1 hour before CST.

Let us convert MST into CST.

Departure = 5:30 pm MST = 6:30 pm CST

Total time travel = Departure – Arrival

= 9.20 pm MST – 6.30 pm MST

= 2 hour 50 minutes

Hence, total time travel is 2 hour 50 minutes.

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4 years ago
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3 years ago
2. Write the ratio as a fraction in simplest form, 20 mi to 32 mi. (picture)​
viktelen [127]

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5 0
3 years ago
A ball is launched upward from a height 40 feet above ground level. The ball’s height at t seconds is given by -16t^2=128=40 .
Nesterboy [21]

Answer:

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

Step-by-step explanation:

<u><em>The correct question is</em></u>

A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?

we have

h(t)=-16t^{2}+128t+40

so

For h(t)=100 ft

substitute in the equation and solve for x

-16t^{2}+128t+40=100

-16t^{2}+128t-60=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+128t-60=0

so

a=-16\\b=128\\c=-60

substitute in the formula

x=\frac{-128(+/-)\sqrt{128^{2}-4(-16)(-60)}} {2(-16)}

x=\frac{-128(+/-)\sqrt{12,544}} {-32}

x=\frac{-128(+/-)112} {-32}

x=\frac{-128(+)112} {-32}=0.5

x=\frac{-128(-)112} {-32}=7.5

therefore

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

7 0
4 years ago
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