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4 years ago

Why is the polynomial, 4x^2y + 5xy classified as a 3rd degree binomial?

1 answer:

6 0

The polynomial has two terms. The exponent of the first term is two. The exponent of the second term would be 1 because 5xy^1 is equal to 5xy.

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The moon is about 382,500km away from Earth. This distance actually varies by about 22,500km. What are the maximum and minimum d

KiRa [710]

Answer:

The minimum distance to the moon is of 360,000 km and the maximum distance is of 405,000 km

Step-by-step explanation:

The maximum distance is found adding the variation.

The minimum distance is found subtracting the variation.

We have that:

Distance: 382,500 km

Variation: 22,500 km

Maximum distance: 382500 + 22500 = 405,000 km

Minimum distance: 382500 - 22500 = 360,000 km

The minimum distance to the moon is of 360,000 km and the maximum distance is of 405,000 km

6 0

3 years ago

Suppose you work in the quality assurance department of a chemical processing plant and it is your responsibility to ascertain w

aleksandrvk [35]

Answer:

48.668 ≤ μ ≤ 63.332

Step-by-step explanation:

Given the data:

Sample (X) : 71, 45, 54, 75, 50, 49, 63, 55, 48, 50

Number of samples (n) = 10

α = 95% = 0.05

Determine the range within which the true mean of the fluid samples from the day shift will be with a 95% confidence

True mean = μ

Confidence interval :

m ± t(α/2 ; df) * s/√n

m - t(α/2 ; df) * s/√n ≤ μ ≤ m + t(α/2 ; df) * s/√n

m = sample mean ; s = sample standard deviation ; df = degree of freedom =(n - 1) = (10 - 1) = 9

Calculating the sample mean and standard deviation using calculator to save computation time :

71, 45, 54, 75, 50, 49, 63, 55, 48, 50

m = 56 ; s = 10.25

m - t(0.05/2 ; 9) * s/√n ≤ μ ≤ m + t(0.05/2 ; df) * s/√n

From t table : t(0.05/2 ; 9) = t(0.025, 9) = 2.262

56-2.262 * (10.25/√10) ≤ μ ≤ 56+2.262 * (10.25/√10)

48.668 ≤ μ ≤ 63.332

6 0

3 years ago

A certain town never has two sunny days in a row. Each day is classified as being either sunny, cloudy (but dry), or rainy. If i

11111nata11111 [884]

Answer:

the proportion of days that are Sunny is 0.2

Step-by-step explanation:

Given the data in the question;

Using markov chain;

3 states; Sunny(1), Cloudy(2) and Rainy(3)

Now, based on given conditions, the transition matrix can be obtained in the following way;

$\left[\begin{array}{ccc}0&0.5&0.5\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]$

so let the proportion of sunny, cloudy and rainy days be S, C and R respectively.

such that, from column 1

S = 0.25C + 0.25R -------------let this be equation 1

from column 2

0.5C = 0.5S + 0.25R

divided through by 0.5

C = S + 0.5R ---------------------- let this be equation 2

now putting equation 2 into equation;

S = 0.25(S + 0.5R) + 0.25R

S = 0.25S + 0.125R + 0.25R

S - 0.25S = 0.375R

0.75S = 0.375R

S = 0.375R / 0.75

S = 0.5R

Therefore,

from equation 2; C = S + 0.5R

input S = 0.5R

C = 0.5R + 0.5R

C = R

Now, we know that, the sum of the three proportion should be equal to one;

S + C + R = 1

since C = R and S = 0.5R

we substitute

0.5R + R + R = 1

2.5R = 1

R = 1/2.5

R = 0.4

Hence, the proportion of days that are Rainy is 0.4

C = R

C = 0.4

Hence, the proportion of days that are Cloudy is 0.4

S = 0.5R

S = 0.5(0.4)

S = 0.2

Hence, the proportion of days that are Sunny is 0.2

8 0

3 years ago

Would you rather have 15/20 of a pizza or 24/32 of a pizza? Really, it wouldn’t matter because both of those fractions are equiv

lana66690 [7]

Answer:

I think all of these are optional answers

Step-by-step explanation:

7 0

3 years ago

Someone help me asap math 10

Ghella [55]

Answer:

x ≈ 25.4 Km

Step-by-step explanation:

Using the tangent ratio in the right triangle on the right

tan54° = $\frac{opposite}{adjacent}$ = $\frac{opp}{17}$ ( multiply both sides by 17 )

17 × tan54° = opp , thus

opp ≈ 23.4

-------------------------------------------

Using the cosine ratio in the right triangle on the left

cos23° = $\frac{adjacent}{hypotenuse}$ = $\frac{23.4}{x}$ ( multiply both sides by x )

x × cos23° = 23.4 ( divide both sides by cos23° )

x = $\frac{23.4}{cos23}$ ≈ 25. 4 Km ( to the nearest tenth )

6 0

4 years ago