I chose addition. I don't know how to solve this.

Mathematics

1 answer:

denpristay [2]3 years ago

3 0

You are given that y=x+1 so simply substituting this value of y into the first equation is the simplest way to start...3x=3y-3 becomes:

3x=3(x+1)-3 perform indicated multiplication on right side

3x=3x+3-3 combine like terms on right side

3x=3x this is true for any real value of x so there are infinitely many solutions.

Which might be easier to see if you divide the first equation by 3...

3x=3y-3 divide entire equation by 3

x=y-1 add 1 to both sides

x+1=y or

y=x+1 which is equal to the second original equation.

So essentially the two equations are the same line, that is why there are infinitely many solutions as each point on one line is equal to the same point on the "other" line.

You might be interested in

Given f of x is equal to the quantity x plus 3 end quantity over the quantity x squared minus x minus 12 end quantity and g(x) =

Westkost [7]

From the given f(x) and g(x), the value of (g-f)(2)=1

Given :

The functions are

$f(x)=\frac{x+3}{x^2-x-12} \\g(x)=log_4(x)$

Lets evaluate (g-f)(2)

$(g-f)(2)=g(2)-f(2)$

To find out g(2), replace 2 for x in g(x) and then replace 2 for x in f(x)

$f(x)=\frac{x+3}{x^2-x-12} \\g(x)=log_4(x)\\x=2\\f(2)=\frac{2+3}{2^2-2-12}=\frac{5}{-10}=-\frac{1}{2} \\\\g(2)=log_4(2)=\frac{1}{2}$

Now we find g(2)-f(2)

$(g-f)(2)=g(2)-f(2)=\frac{1}{2}-\frac{-1}{2} =1$

Learn more : brainly.com/question/15038769

4 0

3 years ago

Solve for x qwertyuiopasdfghjklzcvbnm

Ludmilka [50]

The triangles ABD, ADC and ABC are similar (AA stands for "angle, angle" and means that the triangles have two of their angles equal).

If two triangles have two of their angles equal, the triangles are similar.

Therefore the sides of triangles are in proportion.

$\dfrac{c}{6}=\dfrac{2}{c}$

cross multiply

$c\cdot c=6\cdot2\\\\c^2=12\to c=\sqrt{12}$

Use the Pythagorean theorem for calculate x:

$x^2=2^2+(\sqrt{12})^2\\\\x^2=4+12\\\\x^2=16\to x=\sqrt{16}\to\boxed{x=4}$

8 0

3 years ago

Hippos can weigh up to 5300 pounds. A baby hippo‘s current weight is 2200 pounds. How much weight can he gain? Right and solve a

Valentin [98]

Baby hippo’s current born weights is 2200. Adult hippos can weight up to 5300 pounds. To find how much more the baby hippo can gain, subtract bith numbers.

W=2200-5300.

3 0

3 years ago

What is 8640minutes in days?(remember ,there are 60minutes in an hour and 24 in a day

Free_Kalibri [48]

$8640min (\frac{1 hr}{60 min}) (\frac{1 day}{24 hr}) = 6 days$