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ikadub [295]
3 years ago
7

A colony of 50 bacteria doubles in size every 170 minutes. What will the population be 680 minutes from now?

Mathematics
2 answers:
kkurt [141]3 years ago
8 0
800 bacteria.
________
seraphim [82]3 years ago
4 0
The answer is 800, to know how many time got doubled divide 680 by 170 you will get 4 so you multiply 50 by 2 power 4. That why the answer is 800.

Hope this helps
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Please help I’m a bit confused on this I appreciate answers!
Afina-wow [57]

Answer:

(2x^3)^3=8\cdot x^{9}

Step-by-step explanation:

<u>Properties of Exponents</u>

The property called Power to a Power shows us how to simplify expressions of the type:

(x^n)^m=x^{n*m}

Similarily the property called Power of a product simplifies expressions like:

(x.y)^n=x^n.y^n

The company mentioned in the question uses the expression

(2x^3)^3

millimeters per second to calculate the maximum capacity of a photocell with an area of x^3 square millimeters.

First, use the power of a product property:

(2x^3)^3=2^3\cdot (x^3)^3

Now use the power to a power property:

(2x^3)^3=2^3\cdot x^{3*3}

Operate:

\mathbf{(2x^3)^3=8\cdot x^{9}}

5 0
3 years ago
figure a~figure b:figure a r=4 ft figure b r =2 ft v=352 cu ft fing the volume of figure b for a final exam due at midnight, wil
Amiraneli [1.4K]
It would be A. Hiiiii
5 0
3 years ago
Find the perimeter of this triangle
erik [133]
Perimeter is the distance around a shape. The way you find it is by adding the lengths of every side.

In this case, it is 3+4+5=12 cm
8 0
3 years ago
a fast food restaurnant had 13 pounds of flour if they split rhe flourevenly among three batches of chicken how much flour would
MariettaO [177]
13 lbs shared between 3 batches . . .

13/3 = 4 1/3 lbs each

The two whole numbers would be 4 and 5
6 0
4 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
FromTheMoon [43]

Answer:

The Taylor series is \ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

The radius of convergence is R=3.

Step-by-step explanation:

<em>The Taylor expansion.</em>

Recall that as we want the Taylor series centered at a=3 its expression is given in powers of (x-3). With this in mind we need to do some transformations with the goal to obtain the asked Taylor series from the Taylor expansion of \ln(1+x).

Then,

\ln(x) = \ln(x-3+3) = \ln(3(\frac{x-3}{3} + 1 )) = \ln 3 + \ln(1 + \frac{x-3}{3}).

Now, in order to make a more compact notation write \frac{x-3}{3}=y. Thus, the above expression becomes

\ln(x) = \ln 3 + \ln(1+y).

Notice that, if x is very close from 3, then y is very close from 0. Then, we can use the Taylor expansion of the logarithm. Hence,  

\ln(x) = \ln 3 + \ln(1+y) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{y^n}{n}.

Now, substitute \frac{x-3}{3}=y in the previous equality. Thus,

\ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

<em>Radius of convergence.</em>

We find the radius of convergence with the Cauchy-Hadamard formula:

R^{-1} = \lim_{n\rightarrow\infty} \sqrt[n]{|a_n|},

Where a_n stands for the coefficients of the Taylor series and R for the radius of convergence.

In this case the coefficients of the Taylor series are

a_n = \frac{(-1)^{n+1}}{ n3^n}

and in consequence |a_n| = \frac{1}{3^nn}. Then,

\sqrt[n]{|a_n|} = \sqrt[n]{\frac{1}{3^nn}}

Applying the properties of roots

\sqrt[n]{|a_n|} = \frac{1}{3\sqrt[n]{n}}.

Hence,

R^{-1} = \lim_{n\rightarrow\infty} \frac{1}{3\sqrt[n]{n}} =\frac{1}{3}

Recall that

\lim_{n\rightarrow\infty} \sqrt[n]{n}=1.

So, as R^{-1}=\frac{1}{3} we get that R=3.

8 0
4 years ago
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