Use the identity
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x = 1 + tan^2x - 2 tan x
0 = -2 tanx
tan x = 0
x = 0, π
π is an extraneous root because sec 180 = -1
So the answer is 0 degrees
Answer:
4p^3 (4p + 1)
Step-by-step explanation:
All we can do with this equation is factor it.
16p^4 + 4p^3
When we look at the coefficients, there is a common factor of 4 with 16 and 4. The p's are also common factors, and we can take out a common factor of x^3. We can combine these common factors and take them out of the equation at the same time.
4p^3 (4p + 1)
Answer:
addition
Step-by-step explanation:
idkthis sounds dumb
Answer:
6c^2 + c
Step-by-step explanation:
8^2 - 2c^2= 6c^2
6c-5c = c
Answer:
It is d.
Step-by-step explanation:
May i have brainliest
