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ki77a [65]
4 years ago
14

Defines substitution ​

Mathematics
2 answers:
anastassius [24]4 years ago
8 0

Answer:

the action of replacing someone or something with another person or thing.

Step-by-step explanation:

Kisachek [45]4 years ago
4 0

Answer:

Step-by-step explanation:

Trading one for another :)

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The figure for the other questions
stira [4]
I can't really measure the angles. I can tell you what they look like they'd be. There are three reasons why not. 
1. The paper is slightly bulged where your hand is
2. The circle is slightly distorted by the camera. This  is not that critical. 
3. It is very hard to measure on a computer screen.
There is nothing you could do to make it any better. In fact, given what you had to do, this is a pretty good representation. 

The Three angles -- Question 22
Using the crudest tools you could imagine, I measured the angle where you have written two 90s between the arms as 132°. That angle opens towards the bottom of the page.

The angle that you have called 95 degrees is actually pretty close. I think you read the upper set of numbers on the protractor when you should have been reading the lower set. I make it 89, but I'll bet it is intended to be 90 degrees. 

The third angle on your right is the same as the first one. It comes in at about 132° using my tools again. 

Question 23
I can help you with this. When you are asked to make an equation, you have to use an equal sign somewhere. 

The sum of the three angles should be 360° I'm going to create an error term because I'm almost sure what I measured won't make 360. All circles when you make angles from any point inside them should make angles that add up to 360° when measured with a protractor if the rays of the angles all start from the same point. [If you don't know what a ray is, call it "the arms of the angles"].

So let's create the equation.
Angle1 + angle2 + angle3 + E = 360°
Angle1 = 89° 
Angle2 = 132°
Angle3 = 132°
E is the error that represents the amount away from 360. Your teacher doesn't expect you to get this or to set it into your equation. The main thing you were supposed to do is add up the angles as you tried to do and state what your total was. This is what was expected.
Total = angle1 + angle2 + angle3
Total = 89 + 132 + 132 = 353. My error is 7° too little. So in my equation E = 7°

What to do
Somebody had to mark this with that green felt. You have a teacher. Go to the teacher and ask to be shown how to read the protractor if that person knows. You just need a bit of help. If the teacher cannot tell you, go to someone in your class who knows about that sort of thing and ask them. You're pretty close to getting it.

6 0
3 years ago
Based on the information in the graph, in which month do 24% of the students have a birthday?
creativ13 [48]

Answer:

23

Step-by-step explanation:

8 0
3 years ago
State all integer values of x in the interval (-3, 3] that satisfy the following
Galina-37 [17]

(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x -5/3.

We have given

-3x+4 > 9

Required values of x.

State the values of x within -3 and 3.

subtract 4 from both sides,

-3x+4-4>9-4

<h3>What is the meaning of like terms?</h3>

like terms are terms that have the same variables and powers. The coefficients do not need to match.

Collect Like Terms

-3x > 5

(-3x)(-1)   <   5(-1)

3x  <  -5

Divide both sides by 3

3x/3 < -5/3

x    <   -5/3

(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x is -5/3.

To learn more about the interval visit:

brainly.com/question/12221823

#SPJ1

3 0
2 years ago
Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).
Firdavs [7]

Answer:

A) Particular solution:

2x+\frac{1}{2}e^{-x}-\frac{8}{5}

B) Homogeneous solution:

y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))

C) The most general solution is

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

Step-by-step explanation:

Given non homogeneous ODE is

y''+4y'+5y=10x+e^{-x}---(1)

To find homogeneous solution:

D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)

To find particular solution:

y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\

Substituting y_{p},y'_{p},y''_{p} in (1)

y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\

Equating the coefficients

5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\

The general solution is

y=y_{h}+y_{p}

from (2) ad (3)

y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}

6 0
3 years ago
A linear equation has more than one intercept. what can you conclude about the graph of the equation?
DanielleElmas [232]
A linear equation of the form :

y = mx+b

can have at the most ONE x-intercept and at the most ONE y-intercept

I can conclude that this linear equation DOESN'T pass through the origin (O) and that it intercepts the x-axis as well as the y-axis

5 0
3 years ago
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