Answer:
See explaination
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
this means that size of nut is smaller than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
this means that size of bolt is smaller than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
The answer is D) on Oddessey Ware
Answer:
Here is the program for the given question
Explanation:
class StringSet
{
ArrayList<String> arraylist; //a reference variable of ArrayList of generic type String
//A no argument constructor.
public StringSet()
{
arraylist=new ArrayList<String>(); //instantiating the ArrayList object
}
//A mutator that adds a String newStr to the StringSet object.
void add(String newStr)
{
arraylist.add(newStr); // add(String) method to add string to the arraylist
}
//An accessor that returns the number of String objects that have been added to this StringSet object.
int size()
{
return arraylist.size(); // size() method which gives the number of elements in the list
}
//An accessor that returns the total number of characters in all of the Strings that have been added to this StringSet object.
int numChars()
{
int sum = 0;
for(String str:arraylist) //for-each loop; can be read as for each string in arraylist
{
sum+=str.length();
}
return sum;
}
//An accessor that returns the number of Strings in the StringSet object that have exactly len characters.
int countStrings(int len)
{
int count = 0;
for(String str:arraylist)
{
if(str.length() == len)
count++;
}
return count;
}
}
Answer:
Colon(:) is the correct answer.
Explanation:
The colon(:) is used to contain those fields which is calculated in the queries. In other words, the colon is used to insert the name for that field which is calculated then, the user uses the colon(:) and after that, he uses the expression in the columns or the field row. So, That's why the following option is true.
