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Alexandra [31]
3 years ago
10

What is 37.2+103.+8.52

Mathematics
2 answers:
Mars2501 [29]3 years ago
6 0
The answer is 148.72....
andreev551 [17]3 years ago
4 0
<span>(148.72) without the inclution of the decimal after 103</span>
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8.14÷20 please show work​
saul85 [17]

Answer:

0.407

Step-by-step explanation:

 <u>0. 4 0 7</u>

2 0     /8. 1 4 0

 −<u> 0</u>      

   8 1    

 <u>− 8 0   </u>

     1 4  

  <u> −   0  </u>

     1 4 0

   −<u> 1 4 0</u>

         0

6 0
3 years ago
Read 2 more answers
-36 as a fraction in simplest form
Cerrena [4.2K]

Answer:

-1/2

Step-by-step explanation:


7 0
3 years ago
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Giving brainliest !! *easy*
Zepler [3.9K]

Answer: 49

Step-by-step explanation:

The missing constant term in the perfect square is 49.

x^2 + 14x + 49

We need a squart root of something to make the factor add up equal to 14x. If it's a perfect square, we could divide 14 by 2, 14/2 = 7, and we multiply 7^2, we get 49, which is a perfect square.

4 0
2 years ago
Question regarding logarithms.
Eddi Din [679]

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}

\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}

\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}

6 0
3 years ago
Read 2 more answers
PLEASE HELP<br> solve for V
motikmotik

Answer:

-102.4 = v

Step-by-step explanation:

-15.9 = -3.1 + v/8

Add 3.1 to each side

-15.9 + 3.1 = -3.1+3.1 + v/8

-12.8 = v/8

Multiply each side by 8

-12.8 * 8 = v/8*8

-102.4 = v

7 0
3 years ago
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