The first net because the figure shown is a square pyramid<span />
<span>False. It will choose a larger aperture for quality.</span>
Answer:
The probability distribution is Normal continuous
Step-by-step explanation:
The basic idea is that velocity values have different noise level and an important thing regarding continuous probability distributions is that the probability of the random variable is equal to a specific outcome is 0
In other words, is practically impossible that one value of velocity could be the same as others.
Answer:
Ok, we have a system of equations:
6*x + 3*y = 6*x*y
2*x + 4*y = 5*x*y
First, we want to isolate one of the variables,
As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:
(6*x + 3*y)/(2*x + 4*y) = 6/5
now we isolate one off the variables:
6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y
x*(6 - 12/5) = y*(24/5 - 3)
x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y
Now we can replace it in the first equation:
6*x + 3*y = 6*x*y
6*(0.5*y) + 3*y = 6*(0.5*y)*y
3*y + 3*y = 3*y^2
3*y^2 - 6*y = 0
Now we can find the solutions of that quadratic equation as:
So we have two solutions
y = 0
y = 2.
Suppose that we select the solution y = 0
Then, using one of the equations we can find the value of x:
2*x + 4*0 = 5*x*0
2*x = 0
x = 0
(0, 0) is a solution
if we select the other solution, y = 2.
2*x + 4*2 = 5*x*2
2*x + 8 = 10*x
8 = (10 - 2)*x = 8x
x = 1.
(1, 2) is other solution
Answer:
Step-by-step explanation:
Given that a bag contains 40 cards numbered 1 through 40 that are either red or blue. A card is drawn at random and placed back in the bag.
This is done four times. Two red cards are drawn, numbered 31 and 19, and two blue cards are drawn, numbered 22 and 7.
From the above we cannot conclude that red cards and even numbers are mutually exclusive
Just drawing two red cards and because the two happen to be odd we cannot generalize the red cards have odd numbers.
This might have occurred due to simple chance from a comparatively large number of 40 cards.
Suppose say we have red cards 20, and 19 red 1 blue.
Then drawing 2 from 19 red cards have more probability and this can occur by chance.
So friend's conclusion is wrong.
