All categories

3 years ago

Six oranges cost $1.50. how much does 15 oranges cost?

Mathematics

2 answers:

kati45 [8]3 years ago

4 0

Answer:

3.75 for 15 oranges

Step-by-step explanation:

Hunter-Best [27]3 years ago

4 0

Answer:

3.75

Step-by-step explanation:

We can use a ratio to solve

6 oranges 15 oranges

--------------- = --------------

1.50 x dollars

Using cross products

6x = 1.50 *15

6x =22.5

Divide each side by 6

6x/6 = 22.50/6

x = 3.75

You might be interested in

Geomtry plzzzz help me

victus00 [196]

Step-by-step explanation:

it is an isoceles triangle (equally long legs).

there is a right angle at W, so YW is the height of the isoceles triangle XYZ.

that means W splits XZ in half.

therefore,

ZW = XZ/2 = 38/2 = 19

8 0

3 years ago

What is 1,773 divide by 3 be honest

-BARSIC- [3]

what is 1,773 divide by 3 be honest

Answer:

Step-by-step explanation:

Hope it helps:)

#CarryOnLearning

3 0

3 years ago

Read 2 more answers

Help me please and thank you!

mamaluj [8]

7^6 is the correct answer

8 0

3 years ago

Solve for x x-4=-7. Please

Alecsey [184]

Answer:

-3

Step-by-step explanation:

x - 4 = - 7

Carry over the - 4 and make x the subject.

x= - 7 + 4

x= - 3

Therefore x is - 3

8 0

4 years ago

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

3 years ago

Six oranges cost $1.50. how much does 15 oranges cost?​

Six oranges cost $1.50. how much does 15 oranges cost?