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Ilya [14]
3 years ago
11

Multiply (x + 3)(x - 2)

Mathematics
2 answers:
Tju [1.3M]3 years ago
6 0

Answer:

Step-by-step explanation:

(X+3)(x-2)

3x-2x

X

Ratling [72]3 years ago
6 0

Answer:

=x2+x−6

Step-by-step explanation:

(x+3)(x−2)

=(x+3)(x+−2)

=(x)(x)+(x)(−2)+(3)(x)+(3)(−2)

=x2−2x+3x−6

=x2+x−6

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State whether f is a function
Alenkinab [10]
<h2>Answer:</h2>

y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function

<h2>Step by step solution:</h2>

A function f from a set A to a set B is a relation that assigns to each element x in the set A exactly one element y in the set B. The set A is the domain (also called the set of inputs) of the function and the set B contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function f has an inverse function if and only if there is no any horizontal line that intersects the graph of f at more than one point. So the function is called one-to-one. The graph of f is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find f^-{1}(x):

f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}

and this is not a function because there are elements in the set of inputs that match with two elements in the set of outputs.

5 0
3 years ago
Read 2 more answers
What is the product of the complex numbers (3 + i) and<br> (3 - i)?
dedylja [7]

Answer:

\left(3+i\right)y\left(3-i\right)=10y

Step-by-step explanation:

\left(3+i\right)y\left(3-i\right)

\left(3+i\right)\left(3-i\right)y

=y\cdot \:10

=10y

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Your answe would be 1 9/13
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